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irakobra [83]
3 years ago
6

As less rain fall,does more plants grow?

Chemistry
1 answer:
Vladimir79 [104]3 years ago
6 0
More rain makes for more plant growth, so the answer is no because without water(rain) and nutrients plants can't really grow.

I hope that this helps you !
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WILL MARK AS BRAINIEST PLEASE HELP 20 POINTS
Alisiya [41]

The subscript is the amount of atoms in each molecule and the coefficient is the amount of molecules. there are 4 Hydrogen, 2 Sulfur, and 8 Oxygen in this particular substance.

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Usually, when the temperature is increased, what will happen to the rate of dissolving?
True [87]

Answer:

B) It will increase.

Explanation:

Solubility tends to increase with an increase in temperature

5 0
3 years ago
What is the ph of an aqueous solution with a hydrogen ion concentration of [H+]=1. 2×10^−8 m?
il63 [147K]

The pH of an aqueous solution with a hydrogen ion concentration of [H+]=1. 2×10^−8 m is  7.92.    

The entire form of pH is potential of Hydrogen. pH is called the poor logarithm of H+ ion attention. hence the that means of the name pH is explained because the energy of hydrogen. pH describes the concentration of the hydrogen ions in a solution and it's miles the indicator of acidity or basicity.

pH is an important amount that reflects the chemical conditions of an answer. The pH can manage the provision of vitamins, organic features, microbial activity, and the conduct of chemical substances.

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explaination,

[H+]=1. 2×10^−8 m

log[h+] = 1. 2×10^−8 m

        =   8 - log (1.2)

        =   8 - 0.079

PH  = 7.921    

Learn more about pH here:-brainly.com/question/172153

#SPJ4

4 0
1 year ago
I know #2 is D. I just need to know why
Allushta [10]

B^2 would not be b*2.

7 0
3 years ago
Read 2 more answers
Bromocresol green, Ka=2.0×10−5, is yellow in its protonated form (HX) and blue in its ionized form (X−). At what pH will bromocr
nydimaria [60]

Answer:

pH = 4,70

Explanation:

For bromocresol, as HX is yellow and X⁻ is blue, the indicator will be a perfect green color when HX = X⁻.

Using Henderson-Hasselbalch formula:

pH = pka + log [X⁻]/[HX] <em>(1)</em>

Where pka is -log ka = -log2,0x10⁻⁵ = 4,70

As HX = X⁻, [HX] / [X⁻] = 1

Replacing in (1):

pH = 4,70 + log 1

pH = 4,70 + 0

<em>pH = 4,70</em>

<em></em>

I hope it helps!

4 0
4 years ago
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