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saveliy_v [14]
2 years ago
15

Find the slope of the line that passes through (4, 5) and (6,4)

Mathematics
1 answer:
Dahasolnce [82]2 years ago
7 0

Answer:

-1/2

Step-by-step explanation:

y2-y1       4-5           -1

--------- = --------  = --------

x2-x1        6-4         2

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What is the solution to the equation |x − 4| = 17?
andrey2020 [161]

~~~~~~|x-4| = 17\\\\\implies x -4 = 17~~~~ \text{or}~~~~~ x -4 = -17\\\\\implies x = 17+4~~~~\text{or}~~~~~ x = -17+4\\\\\implies x = 21~~~~~~~~~\text{or}~~~~~x = -13

8 0
1 year ago
In the dig ram below line l is parallel to line m. Which angles are congruent to angle 1
mixas84 [53]

Answer:

3, 8, 6

Step-by-step explanation:

<u>The angles that are congruent to angle 1 are:  3, 8, 6</u>

<u />

Answer:  Congruent angles are 3, 8, 6

4 0
3 years ago
Pepper jackie has 5.8
vesna_86 [32]

Answer:

Pepper Jackie still has 5.8

Step-by-step explanation:

If this is a english problem instead of a math problem to correct the sentence it would be       Pepper Jackie has 5.8

4 0
3 years ago
Will mark Brainliest!! :)
Georgia [21]

Step-by-step explanation:

The system of equations for eq 1 which is 3x + y = 118 represents the Green High School which filled three buses(with a specific number of students identified as x) and a van(with a specific number of students identified as y) with a total of 118 students.

for eq 2; 4x + 2y = 164; represents Belle High School which filled four buses(with a specific number of students identified as x) and two vans(with a specific number of students identified as y) with a total of 164 students.

The solution represents the specific number of students in the buses and vans in eq1 and eq 2 with x being 36 students and y being 10 students.

substituting 36 for x and 10 for y in eq 1;

3(36) + 10 = 108 + 10 = 118 total students for Green High School

substituting 36 for x and 10 for y in eq2;

4(36) + 2(10) = 144 + 20 = 164 total students for Belle High school

6 0
2 years ago
Fiona wrote the linear equation y = 2/5 x – 5. When Henry wrote his equation, they discovered that his equation had all the same
Hoochie [10]

we have

y=\frac{2}{5}x-5

Let's Isolate the variable y in each of the cases and then compare with Fiona's equation  to determine the solution of the problem

case A) x-\frac{5}{4}y= \frac{25}{4}

Multiply by 4 both sides

4x-5y= 25

5y=4x-25

Divide by 5 both sides

y=\frac{4}{5}x-5

therefore

the case A) is not equal to Fiona's equation

case B) x-\frac{5}{2}y= \frac{25}{4}

Multiply by 4 both sides

4x-10y= 25

10y=4x-25

Divide by 10 both sides

y=\frac{2}{5}x-2.5

therefore

the case B) is not equal to Fiona's equation

case C) x-\frac{5}{4}y= \frac{25}{2}

Multiply by 4 both sides

4x-5y= 50

5y=4x-50

Divide by 5 both sides

y=\frac{4}{5}x-10

therefore

the case C) is not equal to Fiona's equation

case D) x-\frac{5}{2}y= \frac{25}{2}

Multiply by 2 both sides

2x-5y= 25

5y=2x-25

Divide by 5 both sides

y=\frac{2}{5}x-5

therefore

the case D) is  equal to Fiona's equation

<u>the answer is</u>

x-\frac{5}{2}y= \frac{25}{2}



7 0
3 years ago
Read 2 more answers
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