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OleMash [197]
2 years ago
10

A car of weight 300N moved through a distance of 10m when pushed by 3 students

Physics
1 answer:
Sati [7]2 years ago
3 0

The work done by the three students is 3,000 J.

The energy transferred in the process is 3,000 J.

<h3>What is work done?</h3>
  • Work done is the product of force and distance moved by the object.

W = Fd

The work done by the three students is calculated as follows;

W = 300 x 10

W = 3,000 J

<h3>What is energy transfer?</h3>
  • This is means by which energy is converted from one form to another.

The energy transferred in the process is determined by work energy theorem.

E = W

E = 3,000 J

Learn more about work-energy theorem here: brainly.com/question/22236101

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What form of matter is "vapor"?
elena55 [62]
Vapor is usually made with water and it would be made with gas. 
4 0
3 years ago
A car weighs 15,000 N, and its tires are inflated to a pressure of 190 kPa.How large is the area of the car's tires that are in
Elan Coil [88]
Pressure is the force applied perpendicular to a surface divided by the area of the surface. Therefore, from the given values, we can easily calculate the area by dividing the force to the pressure. We do as follows:

Area = F / P
Area = 15000 / 190000
Area = 0.0789 m^2

Hope this answers the question. Have a nice day.
7 0
3 years ago
Read 2 more answers
What is your speed (in m/s) if you walk 1000m in 20 minutes? (Hint: how many seconds are in a minute)
labwork [276]

Answer:

20min = 20 × 60 = 1200sec.

Speed in m per sec.

V = 1000/1200

V = 0.833m per sec.

Explanation:

7 0
3 years ago
On a vacation flight, you look out the window of the jet and wonder about the forces exerted on the window. Suppose the air outs
user100 [1]

Answer:

A) \Delta P =  14512.5 Pa = 14.512 kPa

B) F = 1632.65 N

Explanation:

Given details

outside air speed is given as v_2 = 150 m/s

since inside air is atmospheric , v_1 = 0 m/s

a) By using bernoulli equation between outside and inside of flight

P_1 + \frac{1}{2} \rho v_1^2 + \rho gh = P_2 + \frac{1}{2} \rho v_2^2 + \rho gh

\Delta P = \frac{1}{2} \rho v_2^2 - \frac{1}{2} \rho v_1^2

\Delta P = \frac{1}{2} \rho[ v_2^2 -v_1^2]

\Delta P = \frac{1}{2} 1.29 [ 150^2 - 0^2]

\Delta P =  14512.5 Pa = 14.512 kPa

b) force exerted on window

Area of window  = 25\times 45 = 1125 cm^2 = 0.1125 m^2

We know that force is given as

F = P\times A

F = 14512.5 \times 0.1125

F = 1632.65 N

5 0
3 years ago
Find the current if 55 C of charge pass a particular point in a circuit in 5 seconds.
uranmaximum [27]

Answer:

<em>The current is 11 Amperes</em>

Explanation:

<u>Electric Current</u>

The electric current is defined as a stream of charged particles that move through a conductive path.

The current intensity can be calculated as:

\displaystyle I=\frac{Q}{t}

Where:

Q = Electric charge

t   = Time taken by the charge to move through the conductor

The current intensity is often measured in Amperes.

The charge passing through a point in a circuit is Q= 55 c during t=5 seconds, thus the current intensity is:

\displaystyle I=\frac{55}{5}

I = 11 Amp

The current is 11 Amperes

4 0
3 years ago
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