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OleMash [197]
2 years ago
10

A car of weight 300N moved through a distance of 10m when pushed by 3 students

Physics
1 answer:
Sati [7]2 years ago
3 0

The work done by the three students is 3,000 J.

The energy transferred in the process is 3,000 J.

<h3>What is work done?</h3>
  • Work done is the product of force and distance moved by the object.

W = Fd

The work done by the three students is calculated as follows;

W = 300 x 10

W = 3,000 J

<h3>What is energy transfer?</h3>
  • This is means by which energy is converted from one form to another.

The energy transferred in the process is determined by work energy theorem.

E = W

E = 3,000 J

Learn more about work-energy theorem here: brainly.com/question/22236101

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The radar gun measures the frequency of the radar pulse echoing off your car. By what percentage is the measured frequency diffe
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Question: A. The state highway patrol radar guns use a frequency of 9.15 GHz. If you're approaching a speed trap driving 30.1 m/s, what frequency shift will your FuzzFoiler 2000 radar detector see?

B. The radar gun measures the frequency of the radar pulse echoing off your car. By what percentage is the measured frequency different from the original frequency? (Enter a positive number for a frequency increase, negative for a decrease. Just enter a number, without a percent sign.)?

Answer:

The frequency change percentage is 9.94%

Explanation:

The frequency shift can be calculated as follows.

F= \frac{V+V_{0}}{V+V_{s}}

   = 9.05GHz\times\frac{343m/s+0}{343m/s+(-31.3m/s)}

   =9.95 GHz

So the frequency change seen by the detector is 9.95 - 9.05

% difference= \frac{0.9}{9.05} \times100

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The gravitational force between two objects is f. If masses of both objects are halved without changing distance between them, t
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The gravitation force is quartered when two objects' masses are halved without changing their distance.

Gravitational law states that the force of attraction and repulsion between two objects is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

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K= Gravitation force constant

M1M2 = masses of the object

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When M1 and M2 are halved, it becomes M1/2 and M2/2

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F=(K (M1 x M2)/4)/r^2

F=(KM1 x M2)/(4r^2 )

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Therefore

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