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Lana71 [14]
3 years ago
15

Will mark brainliest!!

Mathematics
2 answers:
nlexa [21]3 years ago
6 0
I believe the answer to the question you are asking is true.
taurus [48]3 years ago
4 0

Answer:

I believe it is true

Step-by-step explanation:

I'm not 100% sure but I am like 85% sure that it is true.

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Write the equation of this circle in standard form.<br> please give answer?
Law Incorporation [45]

Given the center (x_0,y_0) and the radius r of a circle, its equation is

(x-x_0)^2+(y-y_0)^2=r^2

In your case, the center is (-4,0), and the radius is 2. Plug these values into the generic formula and you'll get the equation.

3 0
3 years ago
Given f (x) = -3x - 1, solve for x when f (x) = -4
Aleks [24]
Answer:
11
Explanation:
f(x) = -3x - 1 when f(x) = -4
f(x) = -4 * -3 -1 = 12 - 1 = 11
8 0
3 years ago
What are the steps for constructing a copy of an angule only a compass and a straightedge
nlexa [21]
With one point of the compass on the vertex of the angle, draw an arc that intersects both sides of the angle. Draw an arc from each of these points of intersection so that the arcs intersect<span> in the interior of the angle. The compass needs to </span>stay open<span> the same amount throughout this step. 

                           I hoped that help..have a great day:)

</span>
4 0
4 years ago
The perimeter of a rectangle is 53 inches. The combined length of the two shorter sides is 18 inches. What is the length of each
Artist 52 [7]

Answer:

17.5 in

Step-by-step explanation:

Step one:

given

The perimeter of a rectangle is 53 inches

let the two shorter sides be the width w

so w+w= 18in

the two longer sides is L

L+L=2l

Step two:

but the expression for the perimeter of a rectangle is

P=2W+2L

53= 18+2L

53-18=2L

35=2L

divide both sides by 1

L=35/2

L=17.5

7 0
3 years ago
Answer the question in the picture
nekit [7.7K]

Recall the angle sum identities:

\sin(x+y)=\sin x\cos y+\cos x\sin y

\cos(x+y)=\cos x\cos y-\sin x\sin y

Now,

\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}

Divide through numerator and denominator by \cos x\cos y to get

\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}

Next, we use the fact that x,y lie in the first quadrant to determine that

\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2

\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}

So we then have

\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1

Finally,

\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73

4 0
3 years ago
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