Answer:
v = (10 i ^ + 0j ^) m / s, a = (0i ^ - 9.8 j ^) m / s²
Explanation:
This is a missile throwing exercise.
On the x axis there is no acceleration so the velocity on the x axis is constant
v₀ₓ = 10 m / s
On the y-axis velocity is affected by the acceleration of gravity, let's use the equation
v_y =
- g t
at the highest point of the trajectory the vertical speed must be zero
v_y = 0
therefore the velocity of the body is
v = (10 i ^ + 0j ^) m / s
the acceleration is
a = (0 i ^ - g j⁾
a = (0i ^ - 9.8 j ^) m / s²
Answer:
Subtract the atomic number from the mass number
Explanation:
The number of neurons in an atom is equal to the difference between the atomic number and the mass number
Answer:
0 N
Explanation:
This is a trick question, the mass of the wrench would be 0 due to it being in space and has no gravitational pull to weight it down. And since acceleration is defined as the rate and change of velocity with no respect of time and the wrench is moving at a constant velocity, that means the velocity is 0. and since F = m*a it would be F = 0 * 0 = 0 N
Let
denote the position vector of the ball hit by player A. Then this vector has components

where
is the magnitude of the acceleration due to gravity. Use the vertical component
to find the time at which ball A reaches the ground:

The horizontal position of the ball after 0.49 seconds is

So player B wants to apply a velocity such that the ball travels a distance of about 12 meters from where it is hit. The position vector
of the ball hit by player B has

Again, we solve for the time it takes the ball to reach the ground:

After this time, we expect a horizontal displacement of 12 meters, so that
satisfies


Answer:
1) improve the quality of data
2) new system is more simple and elegant
Explanation:
the reason for being selected new system of determining planetary positions are
1) he want to improve the quality of data for having new planetary positioned value.
b) he believed that new system is more simple and elegant for determining planetary positions by both skilled and unskilled user i.e. astronomers and general public