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Bezzdna [24]
3 years ago
12

8. The mass of the sun is 1.99 x 1030 kilograms and its distance from Earth is 150 million kilometers (150 x 109 meters). What i

s the gravitational force between the sun and Earth?
please help
Physics
1 answer:
solmaris [256]3 years ago
4 0

Answer:

F=3.53\times 10^{22}\ N

Explanation:

Given that,

Mass of the Sun, m_1=1.99\times 10^{30}\ kg

The distance of Sun from the Earth, r=150\times 10^9\ m

We know that,

The mass of the Earth, m_2=6\times 10^{24}\ kg

We need to find the gravitational force between the Sun and the Earth.

The formula between two masses is given by :

F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1.99\times 10^{30}\times 6\times 10^{24}}{(150\times 10^9)^2}\\\\F=3.53\times 10^{22}\ N

So, the gravitational force between the Sun and the Earth is 3.53\times 10^{22}\ N

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A hockey puck with a mass of 0.16 kg travels at a velocity of 40 m/s toward a goalkeeper. The goalkeeper has a mass of 120 kg an
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Answer:

Explanation:

Momentum is the product of mass of a body and its velocity.

Given the mass of the puck m1 = 0.16kg

velocity of the puck v1 = 40m/s

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velocity of the goalkeeper v2= 0m/s (goal keeper at rest)

The total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper is expressed as:

m1v1 + m2v2 (their momentum will be added since they collide)

= 0.16(40) + 120(0)

= 0.16(40) + 0

= 6.4kgm/s

Let us calculate their common velocity using the conservation of momentum formula;

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6.4 = (0.16+120)v

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Hence after collision, both objects move at a velocity of 0.053m/s

Momentum of the puck after collision = m1v

Momentum of the puck after collision = 0.16*0.053m/s

Momentum of the puck after collision = 0.0085kgm/s

Momentum of the keeper after collision = m2v

Momentum of the keeper after collision = 120*0.053m/s

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Answer:

The value of the water pressure force on the window is 150,000 N.

Wartość siły nacisku wody na okno wynosi 150000 N.

Explanation:

English Translation

The submarine window has an area of ​​0.3 m2 and is located at a depth at which the pressure exerted by the water column is 500 kPa. Finish the sentence. The value of the water pressure force on the window is.

Solution.

Pressure exerted by a force on a surface area perpendicular to the line of action of that force is given by the formula

P = (F/A)

where F = applied force, in this case, water pressure force on the window = ?

A = Area upon which the force is acting = Area of the window = 0.3 m²

P = 500 kPa = 500,000 Pa

500,000 = (F/0.3)

F = 500,000 × 0.3 = 150,000 N

In Polish/Po Polsku

Ciśnienie wywierane przez siłę na pole powierzchni prostopadłe do linii działania tej siły jest określone wzorem

P = (F / A)

gdzie F = przyłożona siła, w tym przypadku siła nacisku wody na okno =?

A = Obszar, na który działa siła = Powierzchnia okna = 0,3 m²

P = 500 kPa = 500000 Pa

500,000 = (F/0.3)

F = 500,000 × 0.3 = 150,000 N

Hope this Helps!!!

Mam nadzieję że to pomoże!!!

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