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2 years ago

Find the value of x (I need help with both of them pls)

Mathematics

1 answer:

Aleks04 [339]2 years ago

6 0

Answer:

1. x = 21

2. x = 19

Step-by-step explanation:

Since the interior angles of all quadrilaterals add up to 360, all we have to do is add them up and set them equal to 360. Combine like terms and we get

7x + 213 = 360

Which further turns to 7x = 147

So x = 21

For the second problem, it's the same thing

By the end we get 2x + 8 = 46

2x = 38

x = 19

Hope this helps

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Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position

Alenkinab [10]

Answer:

$\cos \theta=-\dfrac{8}{17}$

Step-by-step explanation:

Coordinates of Point b $=(-8,15)$

b lies on the circle whose equation is $x^2+y^2=289$

$x^2+y^2=17^2$

Comparing with the general form a circle with center at the origin: $x^2+y^2=r^2$

The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.

For an angle drawn in standard position through point b,

x=-8 which is negative

y=15 which is positive

Therefore, the angle is in Quadrant II.

$\cos \theta=\dfrac{Adjacent}{Hypotenuse} \\$Adjacent=-8\\Hypotenuse=17\\\cos \theta=\dfrac{-8}{17} \\\cos \theta=-\dfrac{8}{17}$

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Given:

In parallelogram ABCD, two of its vertices are A(-4,0) and B(0,3).

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The equation that represents a line that contain CD.

Solution:

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