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Svetlanka [38]
3 years ago
13

Find the value of x (I need help with both of them pls)

Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0

Answer:

1. x = 21

2. x = 19

Step-by-step explanation:

Since the interior angles of all quadrilaterals add up to 360, all we have to do is add them up and set them equal to 360. Combine like terms and we get

7x + 213 = 360

Which further turns to 7x = 147

So x = 21

For the second problem, it's the same thing

By the end we get 2x + 8 = 46

2x = 38

x = 19

Hope this helps

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The camp cook made 3 1/2 pints of baked beans. Each serving of beans is 1/2 of a pint. How many servings of beans did the cook m
Ilia_Sergeevich [38]

Answer:

The cook made 7 pints

Step-by-step explanation:

Just minus the half pints

5 0
3 years ago
A bag contains yellow marbles and blue marbles, 73 in total. The number of yellow marbles is 7 more than 5 times the number of b
Roman55 [17]

Answer:

number of yellow marbles=62.

Step-by-step explanation:

It is given that in a bag there are yellow marbles and blue marbles and the total number of marbles=73.

Let the number of Blue marbles=x, then according to the question, number of yellow marbles will be =5x+7.

Now, Total number of marbles= number of yellow marbles+number of blue marbles.

⇒73=x+5x+7

⇒73-7=6x

⇒66=6x

⇒x=11

Therefore, numberof blue marbles=x=11 and

number of yellow marbles=5x+7=5(11)+7=55+7=62.

8 0
3 years ago
Can someone help me out
Lapatulllka [165]
I think it is number 2, x^2-x+2
8 0
3 years ago
Find the domain of (f/g)(x) when f(x)=1/x and g(x)=square root x+8
Alex_Xolod [135]

Step-by-step explanation:

all work is pictured/shown

6 0
3 years ago
Read 2 more answers
(\tan ^(2)\theta \cos ^(2)\theta -1)/(1+\cos (2\theta ))=
Vitek1552 [10]

(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))

Recall that

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

so cos²(<em>θ</em>) cancels with the cos²(<em>θ</em>) in the tan²(<em>θ</em>) term:

(sin²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))

Recall the double angle identity for cosine,

cos(2<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

so the 1 in the denominator also vanishes:

(sin²(<em>θ</em>) - 1) / (2 cos²(<em>θ</em>))

Recall the Pythagorean identity,

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

which means

sin²(<em>θ</em>) - 1 = -cos²(<em>θ</em>):

-cos²(<em>θ</em>) / (2 cos²(<em>θ</em>))

Cancel the cos²(<em>θ</em>) terms to end up with

(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>)) = -1/2

7 0
3 years ago
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