It’s unsolvable with out more context. What’s the rest of the problem.
Answer:
Given the function: y=f(x) = 3x+2
when x=-2 at the beginning of the interval [-2, 5],
then;
y = 3x+2 begins at
y= 3(-2)+2 = -6+2= -4.
and
when x=5 at the end of the interval [-2, 5],
y = 3x+2 ends up at
y= 3(5)+2 = 15+2= 17.
So,
y has changed -4 to 17, which is a change of 17-(-4)= 17+4 = 21
and x has changed from -2 to 5, which is a change of 5-(-2)=5+2=7
So, the average rate of change of y with respect to x over the interval
[-2, 5] is given by ;
=
Therefore, the average rate of change y with respect to x over the interval is, 3
Step-by-step explanation:
So we are trying to find the numerator of 42 in relation of 6/7.
42 divided by 7= 6 So 6 x 6 from the numerator of 6/7 = 36.
So 6/7 written as a fraction with a denominator of 42 is 36/42.
F(x) = 2x² - x
f(3) = 2(3)² - 3
f(3) = 2(9) - 3
f(3) = 18 - 3
f(3) = 15
f(x) = 2x² - x
f(5) = 2(5)² - 5
f(5) = 2(25) - 5
f(5) = 50 - 5
f(5) = 45
The answer is C.
