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Ad libitum [116K]
3 years ago
6

Or Solve for q. 5 – 4q ≤ –3

Mathematics
2 answers:
netineya [11]3 years ago
5 0

Answer:

q >= 2

Step-by-step explanation:

5 - 4(2) <= 3

5 - 8 <= 3

3 <= 3

trapecia [35]3 years ago
4 0
Subtract 5 from both sides
-4q < -8
Divide it all by -4 and flip the way your sign faces since you’re dividing by a negative
Your answer is q is greater than or equal to 2
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Four times a difference of 17 and a number is 84.
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4×17-x=84
68-x=84
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A rock is thrown upwards from the edge of a 52 foot cliff and eventually falls to the ground. The graph
Lina20 [59]
The rock's height is increasing in the interval from 0 seconds to 3 seconds.

At time 0 the rock starts moving upward from 52 foot until it reachs 180 foot height (time 3 seconds). Then the rock starts to descend, which means that the height starts to decrease.
5 0
3 years ago
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25 points! First RIGHT answer gets brainliest!
nekit [7.7K]

Answer:

I hope this help :)

Step-by-step explanation:

radius: 2.459

diameter: 38

circumference: 119.381

but if you're looking for a more appropriate answer I would round radius and circumference.

7 0
3 years ago
Read 2 more answers
Can you show me this step by step please
Leya [2.2K]

Answer:

  clockwise from left, the missing side lengths are 8 m, 13 m, 8 m

Step-by-step explanation:

The perimeter of the figure is the sum of the lengths of its sides. Sides with the same hash mark have the same length, so the perimeter (in meters) is ...

  38 = (3x+1) +(2x) +(9) +(2x)

  38 = 7x +10

  28 = 7x . . . . . . subtract 10

  4 = x . . . . . . . . divide by 7

Then the short sides are ...

  2x = 2·4 = 8 . . . meters

and the long side is ...

  3x+1 = 3·4 +1 = 13 . . . meters

5 0
3 years ago
Determine and state the maximum error of the function G(x,y,z)=20 ln⁡(xyz^2 ) using differentials when (x,y,z)=(2,3,4) and given
Leona [35]

Answer:

The maximum error in the function G, ΔG = ±4

Step-by-step explanation:

G(x,y,z) = 20 In (xyz²)

Total or maximum error for a multi-variable function is given by

ΔG = (∂G/∂x) (Δx) + (∂G/∂y) (Δy) + (∂G/∂z) (Δz)

(∂G/∂x) = 20yz²/xyz² = 20/x

(∂G/∂y) = 20xz²/xyz² = 20/y

(∂G/∂z) = 40xyz/xyz² = 40/z

Δx = ±0.10

Δy = ±0.15

Δz = ±0.20

ΔG = (∂G/∂x) (Δx) + (∂G/∂y) (Δy) + (∂G/∂z) (Δz)

ΔG = (20/x) (0.10) + (20/y) (0.15) + (40/z) (0.2)

At the point (x,y,z) = (2,3,4)

ΔG = (20/2) (0.10) + (20/3) (0.15) + (40/4) (0.2) = 10(0.10) + 20(0.05) + 10(0.2) = 1 + 1 + 2 = 4

ΔG = ±4

6 0
3 years ago
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