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valina [46]
3 years ago
13

Balancing Chemical Equations Worksheet

Chemistry
1 answer:
Goshia [24]3 years ago
5 0

The balanced chemical equation of the reactions given is as follows:

  • 2LiHCO3 -----> Li2CO3 + H2O + CO2
  • 2 N2 + 5 O2 -----> 2 N2O5
  • MgBr2 + KOH -----> KBr + Mg(OH)2
  • Mn + 2 CuCl -----> 2 Cu + MnCl2
  • 8 Zn + S8 -----> 8 ZnS
  • 2 NaOH + H2SO4 -----> 2 H2O + Na2SO4
  • 2 K + 2 H2O -----> 2 KOH + H2
  • C5H12 + 8 O2 -----> 6H2O + 5 CO2
  • 2 KOH + H2CO3 -----> 2 H2O + K2CO3
  • C4H802 + 6 O2 -----> 4 H20 + 4 CO2
  • 16 Al + 3 S8 ---> 8 Al2S3

<h3>How to balance chemical equations</h3>

Balancing of chemical equations is the process of adding numerical coefficients in front of moles of reactants and products to ensure that the moles of atoms of elements of the reactants is equal to the moles of atoms of products formed.

The balanced chemical equation of the reactions given is as follows:

  • 2LiHCO3 -----> Li2CO3 + H2O + CO2
  • 2 N2 + 5 O2 -----> 2 N2O5
  • MgBr2 + KOH -----> KBr + Mg(OH)2
  • Mn + 2 CuCl -----> 2 Cu + MnCl2
  • 8 Zn + S8 -----> 8 ZnS
  • 2 NaOH + H2SO4 -----> 2 H2O + Na2SO4
  • 2 K + 2 H2O -----> 2 KOH + H2
  • C5H12 + 8 O2 -----> 6H2O + 5 CO2
  • 2 KOH + H2CO3 -----> 2 H2O + K2CO3
  • C4H802 + 6 O2 -----> 4 H20 + 4 CO2
  • 16 Al + 3 S8 ---> 8 Al2S3

Learn more about balancing of chemical equations at: brainly.com/question/15428811

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\%P/P_{hierro}=41.1\%\\\\\%P/P_{arena}=24.4\%\\\\\%P/P_{cobre}=30.8\%\\\\\%P/P_{aluminio}=0.6\%

Explanation:

¡Hola!

En este caso, dado que estamos tratando con problem sobre porcentaje peso/peso de hierro, arena, cobre y aluminio, primero debemos calcular la masa inicial de estos dos primeros en la mezcla original de acuerdo con:

m_{hierro}=300g*0.60=180g\\\\m_{arena}=300*0.40=120g

Ahora si podemos calcular la masa de la mezcla final como la suma de las masas de todos los constituyentes de la mezcla:

m_T=180g+120g+135g+2.77g=437.77g

Finalmente, podemos calcular los porcentajes P/P como se muestra a continuación:

\%P/P_{hierro}=\frac{180g}{437.77g} *100\%=41.1\%\\\\\%P/P_{arena}=\frac{120g}{437.77g} *100\%=24.4\%\\\\\%P/P_{cobre}=\frac{135g}{437.77g} *100\%=30.8\%\\\\\%P/P_{aluminio}=\frac{g}{437.77g} *100\%=0.6\%

¡Saludos!

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