Answer:
1 : 2
Explanation:
From the question given, we obtained the following information:
T1 = 287°C = 287 +273 = 560K
T1 = 587°C = 587 +273 =860K
V1 = V
V2 =?
V1 /T1 = V2 /T2
V/560 = V2/860
Cross multiply
V2 x 560 = 860 x V
Divide both side by 560
V2 = (860 x V) / 560
V2 = 1.54V = 2V
The ratio of initial to final volume =
V1 : V2
= V : 2V
= 1 : 2
Answer:
F=Air
Explanation:
Because I took the test hope it helps
It's 77C.......................
<span>To produce a molar conversion, you need to know the molar mass of each molecule.
I presume you mean there are 192 grams of O2. The molecular weight of oxygen is 16 g/mol. Therefore, O2 is 32 g/mole.
If there are 192 grams of O2, then:
192 grams x (1 mole/32g) = 6 moles of O2.
To react each mole of oxygen, you need 2 moles of hydrogen (H2). You can see this in the equation 2H2 + O2 --> 2 H20.
To react 6 moles of O2, you need 12 moles of H2.
Now that we have the total moles of hydrogen needed, we now use the molar mass of H2 (2 grams/mole)
12 moles H2 x (2 grams/1 mol H2) = 24 grams of H2.</span>
