Answer:
1.2 mi/hr/sec
Explanation:
<em>a = Vf - Vi / t (formula)</em>
-----------------------------------
6mi/hr - 0 mi/hr 6 mi/hr
a = ____________ = _______ = 1.2 mi/hr/sec
5 sec 5 sec
Answer:3W
If it takes an amount of work W to move two q point charges from infinity to a distance d apart from each other, then how much work should it take to move three q point charges from infinity to a distance d apart from each other?
A) 2W
B) 3W
C) 4W
D) 6W
Explanation: calculating work done,W, in moving two positive q point charges from infinity to a valued distance d from each other is
W = k(+q)(+q)/ d
k is couloumb's constant
work done in moving 3 equal positive charges from infinity to a finite distance is given by
W₂=W₄=W₆=k(+q)(+q)/ d
Total work done, W' =k(+q)(+q)/ d + k(+q)(+q)/ d + k(+q)(+q)/ d
= W + W + W = 3W
Answer:
Newton's first law of motion concerns any object that has no force applied to it.
Explanation:
three laws of motion and the law of universal gravitation.
Answer:
A, the angle of refraction
Answer:
734.16 kg m/
Explanation:
The problem is asking for the Force of pushing off the ground.
- The formula of Force is: F = mass x acceleration
Given = <em>Mass</em>: 600 newtons (N)
<em>Acceleration</em>: 12 m/
We have to convert the mass into kg first. Remember that <u>1 kg is equal to 9.80665 newtons.</u>
Let x be the<em> mass in newtons</em>.
Let's convert: 
x 
= 
= 61.18 kg
Phil's weight is 61.18 kg
Let's go back to finding the force.
F = m x a
F = 61.18 kg x 12 m/
F = 734.16 kg m/
