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Maru [420]
2 years ago
12

I need help on question 5 - 6 - 7 - 8 - 9 - 10 - 11 - 12 please

Mathematics
1 answer:
Keith_Richards [23]2 years ago
4 0

Answer:

The solution is given in the photo

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M is the midpoint of YZ. If YM = x + 3, and YZ = 3x -1, find MZ
Elenna [48]
2(x+3)= 3x-1
2x+6=3x-1
X=7
Therefore
YM = 7+3= 10
And by definition of midpoint YM=MZ so MZ=10
3 0
3 years ago
Tell whether the angles are adjacent or vertical. Then find the value of x. x =?
baherus [9]

Answer:

The triangle of the 360 squared by the square

8 0
3 years ago
Which pair shows equivalent expressions?
Dmitry_Shevchenko [17]

Which pair shows equivalent expressions?

A.2(2/5x + 2)=2 2/5x + 1

B.2(2/5x + 2)=4/5x + 4

C.2(2/5x + 4)=4/5x + 2

D.2(2/5x + 4)=2 2/5x + 8

Solution:

2(\frac{2}{5}x + 2)

Let us distribute 2 inside the parenthesis.

That is, we use distributive property:

a(b+c)=ab+ac

2(\frac{2}{5}x + 2) =\frac{2*2}{5}x+2*2

So, 2(\frac{2}{5}x + 2) =\frac{4}{5}x+4

Answer:Option (b)

2(\frac{2}{5}x+4)

Applying distributive property, a(b+c)=ab+ac

2(\frac{2}{5}x+4) =2*\frac{2}{5} x+2*4

2(\frac{2}{5}x+4) =\frac{2*2}{5} x+2*4

2(\frac{2}{5}x+4) =\frac{4}{5} x+8

So, Option (B) is correct.

8 0
3 years ago
Read 2 more answers
The claim is that the standard deviation of the speeds of drivers in Bradford is 8 mph. An experienced driver feels that this is
Irina-Kira [14]

Answer:

Null hypothesis is rejected. Standard deviation is > 8 miles per hour

Step-by-step explanation:

σ [Population standard deviation] = 8 , s [sample standard deviation] = s

n [no of items] = 8

H0 [Null] : σ = 8 ; H1 [Alternate - Right Tail] : σ > 8

χ2 = (n - 1) . s^2 / σ^2

= 49 x (10.5)^2 / 82 = 5402.25 / 64

χ2 = 84.410

df [degree of freedom] = n -1 = 50 - 1 = 49

P value (χ^2 49 > 84.410) = 0.00125

p = 0.0013

p < α ie 0.05

So, H0 is rejected

Hence we state that standard deviation is > 8 miles per hpur

6 0
3 years ago
Daniel worked for 2 1/3 hours and earned $18.20.
andriy [413]
He gets 7.80 an hour so you multiply 7.8 by 5.25 hours
6 0
4 years ago
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