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natta225 [31]
2 years ago
13

Convert 2.8 x10^27 molecules of N2O5 to grams

Chemistry
1 answer:
liraira [26]2 years ago
5 0

Answer:

2.41 molecules

Have a good day

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If 73.5 mL of 0.200 M KI(aq) was required to precipitate all of the lead(II) ion from an aqueous solution of lead(II) nitrate, h
frutty [35]

Answer:

There were 0.00735 moles Pb^2+ in the solution

Explanation:

Step 1: Data given

Volume of the KI solution = 73.5 mL = 0.0735 L

Molarity of the KI solution = 0.200 M

Step 2: The balanced equation

2KI + Pb2+ → PbI2 + 2K+

Step 3: Calculate moles KI

moles = Molarity * volume

moles KI = 0.200M * 0.0735L = 0.0147 moles KI

Ste p 4: Calculate moles Pb^2+

For 2 moles KI we need 1 mol Pb^2+ to produce 1 mol PbI2 and 2 moles K+

For 0.0147 moles KI we need 0.0147 / 2 = 0.00735 moles Pb^2+

There were 0.00735 moles Pb^2+ in the solution

3 0
3 years ago
Electrons can jump between energy levels but can never be found in what energy level
yawa3891 [41]

Answer:

Electrons can jump from energy level to energy level (for example energy level 1 to 2) but they can NEVER be found in between energy levels.

6 0
2 years ago
Please help me with this question!<br> Am I right?
muminat
You are right!! Good job!!!
5 0
3 years ago
How many ml of 2.50 m hno3 are needed to prepare a 75.0 ml of 1.00 m hno3?
frez [133]
M1 * v1 = m2 * v2 
<span>2.50 * v1 = 1 * 75 
</span>2.50 * v1 = 75
2.50 * v1 /75= 75/75
<span>v1= 30 ml

The Answer is 30 ml</span>
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To help decrease food shortages and food insecurity, why might governments encourage their people to adopt vegetarian diets?
Leviafan [203]

Answer:

A is correct but I also think d also correct

5 0
2 years ago
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