1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
son4ous [18]
3 years ago
11

Why is the answer C for this problem?

Chemistry
1 answer:
pshichka [43]3 years ago
4 0

Answer:

\boxed{\text{(C) X}$_{3}$P$_{2}}

Explanation:

Step 1. Identify the Group that contains X

We look at the consecutive ionization energies and hunt for a big jump between them

\begin{array}{crc}n & IE_{n} & IE_{n} - IE_{n-1}\\1 & 730 & \\2 & 1450 & 720\\3 & 7700 & 6250\\4 & 10500 & 2800\\\end{array}

We see a big jump between n = 2 and n = 3. This indicates that X has two valence electrons.

We can easily remove two electrons, but the third electron requires much more energy. That electron must be in the stable, filled, inner core.

So, X is in Group 2 and P is in Group 15.

Step 2. Identify the Compound

X can lose two valence electrons to reach a stable octet, and P can do the same by gaining three electrons.

We must have 3 X atoms for every 2 P atoms.

The formula of the compound is \boxed{\text{X}$_{3}$P$_{2}}$}.

You might be interested in
UHH what in the world is this??? i dont even know when we were assigned to do this!!ughh plz help
vodomira [7]
First row: HCl, ZnCl2, FeCl3, AlCl3, BaCl2, PbCl4

Second row: H3P, Zn3P2, FeP, AlP, Ba3P2, Pb3P4

Third row: HNO3, Zn(NO3)2, Fe(NO3)3, Al(NO3)3, Ba(NO3)2, Pb(NO3)4

Fourth row: ZnO, Fe2O3, Al2O3, BaO, PbO2

Fifth row: HCaF2, Zn(CaF2)2, Fe(CaF2)3, Al(CaF2)3, Ba(CaF2)2, Pb(CaF2)4

Sixth row: H2SO4, ZnSO4, Fe2(SO4)3, Al2(SO4)3, BaSO4, Pb(SO4)2
7 0
3 years ago
Read 2 more answers
Copper sulfate is a blue solid that is used to control algae growth. Solutions of copper sulfate that come in contact with the s
True [87]

Answer:

185.49 grams of Zinc would react with 454g (1lb) of copper sulfate

Explanation:

Yo know the following balanced reaction:

CuSO₄(aq)+ Zn(s) →Cu(s) + ZnSO₄(aq)

You can see that by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagents and products are part of the reaction:

  • CuSO₄: 1 mole
  • Zn: 1 mole
  • Cu: 1 mole
  • ZnSO₄: 1 mole

Being:

  • Cu: 63.54 g/mole
  • S: 32 g/mole
  • O: 16 g/mole
  • Zn: 65.37 g/mole

the molar mass of the compounds participating in the reaction is:

  • CuSO₄:63.54 g/mole + 32 g/mole + 4*16 g/mole= 159.54 g/mole ≅ 160 g/mole
  • Zn: 65.37 g/mole
  • Cu: 63.54 g/mole
  • ZnSO₄: 65.37 g/mole + 32 g/mole + 4*16 g/mole= 161.37 g/mole

Then, by stoichiometry of the reaction, the following amounts of mass of reagent and product participate in the reaction:

  • CuSO₄: 1 moles* 160 g/mole= 160 g
  • Zn: 1 mole* 65.37 g/mole= 65.37 g
  • Cu: 1 mole* 63.54 g/mole= 63.54 g
  • ZnSO₄: 1 mole* 161.37 g/mole= 161.37 g

Now you can apply the following rule of three: if 160 grams of CuSO₄ react with 65.37 grams of Zn by this reaction stoichiometry, 454 grams of CuSO₄ with how much mass of Zn will it react?

mass of Zn=\frac{454 grams of CuSO_{4} *65.37 grams of Zn}{160 grams of CuSO_{4}}

mass of Zn= 185.49 grams

<u><em>185.49 grams of Zinc would react with 454g (1lb) of copper sulfate</em></u>

4 0
3 years ago
Choose two of the following scientists: Anton Lavoisier, John Dalton, JJ Thomson, Robert Millikan, Ernest Rutherford, James Chad
OverLord2011 [107]

Ernest Rutherford

J. J Thomson

Explanation:

<u>Ernest Rutherford</u>

In 1911, Ernest Rutherford, a New Zealand chemist performed the gold foil experiment where he gave the modelling of the atom a boost.

 Experiment

 In his experiment, he bombarded a thin gold foil with alpha particles generated from a radioactive source. He found that most of the alpha particles passed through the gold foil while a few of them were deflected back.

 Discovery and reflection on the atomic theory

To account for his observation, Rutherford suggested an atomic model in which an atom has small positively charged center where nearly all the mass is concentrated.

<u>J. J Thomson</u>

Experiment

In 1897 J.J Thomson performed experiments using the gas discharge tube that led to the discovery of the electrons. He called them cathode rays because they originate from the cathode and exits at the anode.

Discovery and reflection on the atomic theory

From his experiment on the gas discharge tube, Thomson was able determine the properties of cathode rays some of which are:

  • they move in a straight line
  • they possess kinetic energy
  • they attract positive charges and repels negative charges

Using his observation, he proposed the plum pudding model of the atom where it is made up of entirely electrons.

learn more:

Rutherford brainly.com/question/1859083

#learnwithBrainly

6 0
3 years ago
If an object is travelling 25.0 meters/second, how far will it travel in 45 minutes?
Misha Larkins [42]
  • Speed=25m/s
  • Time=45min=(45×60)s=2700s

\\ \rm\longmapsto Distance=Speed(Time)

\\ \rm\longmapsto Distance=25(2700)

\\ \rm\longmapsto Distance=67500m

4 0
2 years ago
when 6.25 grams of pure iron are allowed to react with oxygen , a black oxide forms. if the product weighs 8.15 g, what is the e
erik [133]
We are given with the mass of  pure iron that reacts with oxygen to form an oxide which has a given mass as well. the mass of oxygen reacted is 8.15-6.25 g or 1.9 grams. THen we convert the mass of the reactants to moles. Iron is equal to 0.1119 moles and oxygen is equal to 0.1188. We divide each number to the less amount. Hence iron is 1 and oxygen is approx 1. The empirical formula hence is FeO or ferrous oxide or Iron (II) oxide.
5 0
2 years ago
Other questions:
  • Complete the reactions to show how butanoic acid may be converted to butanal.
    9·1 answer
  • How is a lithium atom (Li) different from a lithium ion (Li+)
    6·2 answers
  • How do I find the chemical formula?
    8·1 answer
  • A few drops of a mixture of sodium hydroxide(NaOH) solution and copper (II) tetraoxosulphate (VI) solution were added to a sampl
    15·1 answer
  • Consider water at 500 kPa and a specific volume of 0.2 m3/kg, what is the temperature (in oC)?
    9·1 answer
  • Which substance is an inorganic compound
    8·1 answer
  • PLEASE HELP
    14·1 answer
  • If a 200 kg person stands next to a 100 kg person. Which person would have a larger gravitational attraction?
    14·2 answers
  • The dictionary from #2 falls off the table. How much kinetic energy does it have just before it hits the floor?
    14·1 answer
  • Energy and cemical reaction short answer <br>​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!