Answer:
b. using less water
Explanation:
Pollution can be defined as the physical degradation or contamination of the environment through an emission of harmful, poisonous and toxic chemical substances.
In the United States of America, the agency which was established by US Congress and saddled with the responsibility of overseeing all aspects of pollution, environmental clean up, pesticide use, contamination, and hazardous waste spills is the Environmental Protection Agency (EPA). Also, EPA research solutions, policy development, and enforcement of regulations through the resource Conservation and Recovery Act.
In homes and offices, an effective and efficient design of pipes and other water-related facilities would go a long way to reduce water pollution because the water used are well managed and properly disposed into sinkholes.
Hence, more efficient plumbing reduces water pollution by using less water
Answer: Contamination
Explanation: This is a known contrainst when performing transformation in the lab. Normally the Pglo plasmid asides glowing under UV, possess a Amp gene that codes for resistance to the antibiotics Ampicillin. Transform cells will survive while untransformed cells will normally die. If untransformed (non glowing, non Ampicillin resistant) cells thrive in the medium, it is definitely a case of contamination. Start again but this time, disinfect appropriately bad be cautious of any potential contamination.
Answer:
due to the overlaying layers of strata (layers of earth) an high pressure is created at the core. due to this it behaves like an solid rether than being a liquid... the lower mantle is not solid because in this case the overlaying strata doesn't produce that much pressure on it..
Explanation:
brainliest plz
When the moles of CH3COOH = volume of CH3COOH * no.of moles of CH3COOH
moles of CH3COOH = 35ml * 0.15 m/1000 =0.00525 mol
moles of NaOH = volume of NaOH*no.of moles of NaOH
= 17.5 ml * 0.15/1000 = 0.002625
SO the reaction after add the NaOH:
CH3COOH(aq) +OH- (aq) ↔ CH3COO-(aq) +H2O(l)
initial 0.00525 0 0
change - 0.002625 +0.002625 +0.002625
equilibrium 0.002625 0.002625 0.002625
When the total volume = 35ml _ 17.5ml = 52.5ml = 0.0525L
∴[CH3COOH] = 0.002625/0.0525 = 0.05m
and [CH3COO-]= 0.002625/0.0525= 0.05 m
when PKa = -㏒Ka
= -㏒1.8x10^-5 = 4.74
by substitution in the following formula:
PH = Pka + ㏒[CH3COO-]/[CH3COOH]
= 4.74 + ㏒(0.05/0.05) = 4.74
∴PH = 4.74
