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snow_lady [41]
2 years ago
5

2 CO + O2= CO2balance or not?​

Chemistry
2 answers:
suter [353]2 years ago
7 0

Answer:

No, The equation is not balanced

The correct ans is

2CO+O2=2CO2

nika2105 [10]2 years ago
7 0

Answer:

No equation is not balanced.2 CO+O2=2CO2

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The specific heat of a given substance
Lelechka [254]
The specific heat is the amount of heat per unit mass required to raise the temperature to 1 degree Celsius. (This is from google)
7 0
3 years ago
ammonia gas is used as refrigerant 0.474 atm. Pressure is required to change 2000 cm3 sample of ammonia initially at 1.0 atm to
Andreas93 [3]

Answer: The pressure required is 0.474 atm

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}V}   (At constant temperature and number of moles)

The equation is,

{P_1V_1}={P_2V_2}

where,

P_1 = initial pressure of gas = 1.0 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 2000cm^3

V_2 = final volume of gas = 4.22dm^3=4220cm^3    (1dm^3=1000cm^3)

Now put all the given values in the above equation, we get:

{1.0\times 2000}={P_2\times 4200}

P_2=0.474atm

The pressure required is 0.474 atm

5 0
2 years ago
How many grams of Carbon are in sample of 400 grams of Co2?​
RoseWind [281]

Answer:

Mass of carbon = 109.1 g

Explanation:

Given data:

Mass of carbondioxide = 400 g

Mass of carbon = ?

Solution:

Molar mass of carbon = 12 g/mol

Molar mass of CO₂ = 44 g/mol

Mass of carbon in 400g of  CO₂:

Mass of carbon = 12 g/mol/44 g/mol × 400 g

Mass of carbon = 109.1 g

3 0
3 years ago
The reaction 2NO(g)+Cl2(g)→2NOCl(g) is carried out in a closed vessel. If the partial pressure of NO is decreasing at the rate o
Luba_88 [7]

Answer : The rate of change of the total pressure of the vessel is, 10.5 torr/min.

Explanation : Given,

\frac{d[NO]}{dt} =21 torr/min

The balanced chemical reaction is,

2NO(g)+Cl_2(g)\rightarrow 2NOCl(g)

The rate of disappearance of NO = -\frac{1}{2}\frac{d[NO]}{dt}

The rate of disappearance of Cl_2 = -\frac{d[Cl_2]}{dt}

The rate of formation of NOCl = \frac{1}{2}\frac{d[NOCl]}{dt}

As we know that,

\frac{d[NO]}{dt} =21 torr/min

So,

-\frac{d[Cl_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}

\frac{d[Cl_2]}{dt}=\frac{1}{2}\times 21torr/min=10.5torr/min

And,

\frac{1}{2}\frac{d[NOCl]}{dt}=\frac{1}{2}\frac{d[NO]}

\frac{d[NOCl]}{dt}=\frac{d[NO]}=21torr/min

Now we have to calculate the rate change.

Rate change = Reactant rate - Product rate

Rate change = (21 + 10.5) - 21 = 10.5 torr/min

Therefore, the rate of change of the total pressure of the vessel is, 10.5 torr/min.

8 0
3 years ago
How many grams of aluminum are necessary to produce 11 L of hydrogen gas at STP?? <br> PLEASE HELP
-BARSIC- [3]
9.0 grams will produce 11 L of hydrogen
6 0
2 years ago
Read 2 more answers
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