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serg [7]
3 years ago
5

How are galaxies organized and distributed within the universe

Physics
2 answers:
den301095 [7]3 years ago
3 0
The galaxies aren't distributed randomly throughout the universe but they are grouped in gravitationally bound clusters.
Mars2501 [29]3 years ago
3 0

Answer:

<u><em>The answer is</em></u>:<em><u> </u></em><u>Many are associated in pairs, trios, groups or clusters, and their distribution in filamentary structures.</u>

<u></u>

Explanation:

<em>Galaxies rarely appear isolated and their distribution in the Universe is not uniform</em>. Many are associated in pairs, trios, groups of some tens or clusters of up to a few thousand. <em>These groups are held together by gravitation. </em>

The large-scale distribution of galaxies seems to indicate that they are concentrated along large filamentary structures.

<u><em>The answer is</em></u>:<em><u> </u></em><u>Many are associated in pairs, trios, groups or clusters, and their distribution in filamentary structures.</u>

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A car that weighs 1.0 x 10^4 N is initially moving at a speed of 38 km/h when the brakes are applied and the car is brought to a
hram777 [196]

Answer:

Part a) Force on car = 2833.84 Newtons

Part b) Time to stop the car = 3.8 seconds

Part c) Factor for stopping distance is 4.

Part d) Factor for stopping time is 1.

Explanation:

The deceleration produced when the car is brought to rest in 20 meters can be found by third equation of kinematics as

v^2=u^2+2as

where

v = final speed of the car ( = 0 in our case since the car stops)

u = initial speed of the car = 38 km/hr =\frac{38\times 1000}{3600}=10.56m/s

a = deceleration produces

s = distance in which the car stops

Applying the given values we get

0^2=10.56^2+2\times a\times 20\\\\a=\frac{0-10.56^2}{2\times 20}\\\\\therefore a=-2.78m/s^2

Now the force can be obtained using newton's second law as

Force=\frac{Weight}{g}\times a

Applying values we get

Force=\frac{1.0\times 10^4}{9.81}\times -2.78\\\\\therefore F=-2833.84Newtons

The negative direction indicates that the force is opposite to the motion of the object.

Part b)

The time required to stop the car can be found using the first equation of kinematics as

v=u+at with symbols having the same meanings

Applying values we get

0=10.56-2.78\times t\\\\\therefore t=\frac{10.56}{2.78}=3.8seconds

Part c)

From the developed relation of stopping distance we can see that the for same force( Same acceleration) the stopping distance is proportional to the square of the initial speed thus doubling the initial speed increases the stopping distance 4 times.

Part d)

From the relation of stopping time and the initial speed we can see that the stopping distance is proportional initial speed thus if we double the initial speed the stopping time also doubles.

8 0
3 years ago
Which radioisotope is used in dating geological formations?
ziro4ka [17]
<h2>Answer: U-238</h2>

Explanation:

Let's begin by explaining that for radioactive geological dating (also called radioisotope dating) in which radioactive impurities were selectively incorporated when the fossil materials were formed, it is very useful to compare it with a naturally occurring radioisotope having a known half-life.

Now, taking into account that the <u>fossils are millions and millions of years old, radioisotopes are needed that exceed this measure. </u>

To understand it better:

The longer the half-life of a radioisotope, the greater its utility for estimating fossil ages or geological formations.

In this sense, uranium-238 (U238) has a half-life of 4,470 million years, therefore, it is among the most commonly used radioisotopes for fossil and geological dating.

6 0
3 years ago
A.
V125BC [204]

Answer:

All the planets orbit the Sun in nearly the same plane.

7 0
3 years ago
Identify the names, charges, and location of three types of subatomic particles that make up an atom.
Eva8 [605]

Answer:Proton (charge of +e, in the nucleus), Neutron (0 charge, in the nucleus), and Electron (charge of –e, outside the nucleus).Nov 13, 2015

Explanation: YA

3 0
2 years ago
Read 2 more answers
g The current through a 10 m long wire has a current density of 4 cross times 10 to the power of 6 space open parentheses bevell
olga55 [171]

Answer:

The value is V  =  2 V

Explanation:

From the question we are told that

The length of the wire is l = 10 \ m

The current density is J =  4*10^6 \  A/m^2

The conductivity is \sigma  =  2*10^{7} \  S/m

Generally conductivity is mathematically represented as

\sigma  =  \frac{l}{RA}

Here R is the resistance which is mathematically represented as

R =  \frac{V}{I}

Here I is the current which is mathematically represented as

I  =  J * A

So

R =  \frac{V}{  J * A}

And

\sigma  =  \frac{l}{\frac{V}{  J * A} * A}

=> \sigma  =  \frac{l}{\frac{V}{J}}

=> V = \frac{l * J}{\sigma }

=> V = \frac{10  * 4*10^6}{2*10^{7}  }

=> V  =  2 V

5 0
3 years ago
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