The age of the bone is 45840 years.
We'll begin by calculating the number of half-lives that has elapsed.
Amount remaining (N) = 0.3125 g
Initial amount (N₀) = 80 g
<h3>Number of half-lives (n) =? </h3>
N × 2ⁿ = N₀
0.3125 × 2ⁿ = 80
Divide both side by 0.3125
2ⁿ = 80 / 0.3125
2ⁿ = 256
2ⁿ = 2⁸
<h3>n = 8</h3>
Thus, 8 half-lives has elapsed
Finally, we shall determine the age of the bone.
Half-life (t½) = 5730 years
Number of half-lives (n) = 8
<h3>Time (t) =? </h3>
t = n × t½
t = 8 × 5730
<h3>t = 45840 years </h3>
Therefore, the age of the bone is 45840 years.
Learn more on half-life: brainly.com/question/15900105
Answer:
The maximum altitude reached with respect to the ground = 0.5 + 0.510 = 1.01 km
Explanation:
Using the equations of motion,
When the rocket is fired from the ground,
u = initial velocity = 0 m/s (since it was initially at rest)
a = 10 m/s²
The engine cuts off at y = 0.5 km = 500 m
The velocity at that point = v
v² = u² + 2ay
v² = 0² + 2(10)(500) = 10000
v = 100 m/s
The velocity at this point is the initial velocity for the next phase of the motion
u = 100 m/s
v = final velocity = 0 m/s (at maximum height, velocity = 0)
y = vertical distance travelled after the engine shuts off beyond 0.5 km = ?
g = acceleration due to gravity = - 9.8 m/s²
v² = u² + 2gy
0 = 100² + 2(-9.8)(y)
- 19.6 y = - 10000
y = 510.2 m = 0.510 km
So, the maximum altitude reached with respect to the ground = 0.5 + 0.510 = 1.01 km
Hope this helps!!!
Explanation:
v ^2 - u ^2 = 2 a s
- u ^2 = 2 * - 9.8 * 0.411
- u ^2 = - 8.0556
u = √8.0556
u = 2.83 m / sec
It is Zn+2HCl....ZnCl2+H2.
3Ca(OH)2+2H3PO4 ....Ca3(PO4)2+6H2O
