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4vir4ik [10]
3 years ago
6

if the volume of a gas contracted from 648 mL to 0.15L, what was its final pressure if it started at a pressure of 485 kpa

Chemistry
1 answer:
bija089 [108]3 years ago
4 0

Answer:

2100 kPa

Explanation:

The temperature is constant, so the only variables are pressure and volume.

We can use Boyle’s Law.

p₁V₁ = p₂V₂     Divide both sides of the equation by V₂

p₂ = p₁ × V₁/V₂  

p₁ = 485 kPa; V₁ =              648 mL  

p₂ = ?;            V₂ = 0.15 L = 150 mL      Calculate p₂

p₂ = 485 × 648/150

p₂ = 2100 kPa

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Answer:

.Heat energy can be transferred from one object to another. The transfer or flow due to the difference in temperature between the two objects is called heat.

Explanation:

The transfer of thermal energy is called heat. In this process, thermal energy moves through a substance.  For example, an ice cube has heat energy and so does a glass of lemonade.

6 0
3 years ago
When 7.085 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.71 grams of CO2 and 10.37 grams of H
Taya2010 [7]

Answer:

- Empirical:

C_3H_7

- Molecular:

C_6H_{14}

Explanation:

Hello,

In this case, based on the information regarding the combustion, the moles of carbon turn out:

n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC

Moreover, the moles of hydrogen:

n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

C_3H_7

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

C_6H_{14}

Which is hexane.

Best regards.

6 0
4 years ago
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A reaction where Oxygen is a reactant.
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6 0
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A gas occupies 3.5L at 2.5 kPa pressure. What is the volume at 100 mmHg at the same temperature? Be sure to
nasty-shy [4]

The volume at 100 mmHg : 0.656 L

<h3>Further explanation</h3>

Boyle's Law  

<em>At a constant temperature, the gas volume is inversely proportional to the pressure applied  </em>

\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}

V₁=3.5 L

P₁=2.5 kPa=18,7515 mmHg

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\tt \dfrac{18.7515}{100}=\dfrac{V_2}{3.5}\\\\V_2=\dfrac{18.7515\times 3.5}{100}=0.656~L

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3 years ago
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