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Trava [24]
3 years ago
9

How many ml of 0.15 M NaOH are required to neutralize 50ml of 2.2 M HC1? ​

Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:

Required: 0.15 M NaOH, 733.3 mL

Explanation:

See attached image below for explanation and how to work it out.

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If you had 10.00 mL of acetic acid that you titrated with .100 M NaOH, and you used 45.15 mL of that base to get a light pink co
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Answer:

0.4515 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

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V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

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Using the above formula , the molarity of acid , can be calculated as ,

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M₁ * 10.0mL = 0.100 M  * 45.15 mL  

M₁ = 0.4515 M

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