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Trava [24]
3 years ago
9

How many ml of 0.15 M NaOH are required to neutralize 50ml of 2.2 M HC1? ​

Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:

Required: 0.15 M NaOH, 733.3 mL

Explanation:

See attached image below for explanation and how to work it out.

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s344n2d4d5 [400]

Answer:

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4 0
3 years ago
The empirical formula of an organic compound is C2H4O. The molecular mass of the compound is 176g/mol.
Brrunno [24]

Answer:

The molecular formula of the compound is C_{8}H_{16}O_{4}. The molecular formula is obtained by the following expression shown below

\textrm{Molecular formula }= n\times \textrm{Empirical formula}

Explanation:

Given molecular mass of the compound is 176 g/mol

Given empirical formula is  C_{2}H_{4}O

Atomic mass of carbon, hydrogen and oxygen are 12 u , 1 u and 16 u respectively.

Empirical formula mass of the compound = \left ( 2\times12+4+16 \right ) \textrm{ u} = 44 \textrm{ g/mol}

n = \displaystyle \frac{\textrm{Molecular formula mass}}{\textrm{Empirical formula mass}} \\n = \displaystyle \frac{176}{44} = 4

\textrm{Molecular formula }= n\times \textrm{Empirical formula}

Molecular formula = 4 \times C_{2}H_{4}O

Molecular formula is C_{8}H_{16}O_{4}

6 0
3 years ago
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Ugo [173]

Answer:

2nd option

Explanation:

7 0
3 years ago
Which of the following is not a characteristic of reliable science?
natta225 [31]

Answer:

Paid sponsorship by a company.

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4 0
3 years ago
What is the volume of 33.25g of butane gas at 293 C and 10.934 kPa?
PSYCHO15rus [73]

Answer:

V = 240.79 L

Explanation:

Given data:

Volume of butane = ?

Temperature = 293°C

Pressure = 10.934 Kpa

Mass of butane = 33.25 g

Solution:

Number of moles of butane:

Number of moles = mass/ molar mass

Number of moles = 33.25 g/ 58.12 g/mol

Number of mole s= 0.57 mol

Now we will convert the temperature and pressure units.

293 +273 = 566 K

Pressure = 10.934/101 = 0.11 atm

Volume of butane:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

V = nRT/P

V = 0.57 mol × 0.0821 atm.L/ mol.K  ×566 K  / 0.11 atm

V = 26.49 L/0.11

V = 240.79 L

6 0
3 years ago
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