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harina [27]
2 years ago
8

.

Physics
1 answer:
WARRIOR [948]2 years ago
8 0

Answer:

Explanation:distance-time =speed

a,V =s/t

V=2m/2s

V=1m/s

b,v=s/t

V=80m/40s

V= 2m/s

The average speed is 2m/s

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What is the moment of inertia i of this assembly about the axis through which it is pivoted?
vivado [14]

Answer:

I = \frac{1}{12}m_t(2x)^2+m_1x^2+m_2x^2

Explanation:

The moment of inertia for the beam is:

I = \frac{1}{12}m_tL^2

Where m_t is the mass of the beam and L is the lengh of the beam

note:

L = 2x

And for particles I is equal to:

I = MR^2

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Finally, the moment of inertia for this assembly is the sum of the moment of inertia of the particles and the beam. So:

I = \frac{1}{12}m_t(2x)^2+m_1x^2+m_2x^2

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