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Elis [28]
3 years ago
9

Light from a helium-neon laser (λ = 633 nm) is used to illuminate two narrow slits. The interference pattern is observed on a sc

reen 3.00 m behind the slits. Eleven bright fringes are seen, spanning a distance of 52.0 mm. What is the spacing (in mm) between the slits?
Physics
1 answer:
stepladder [879]3 years ago
7 0

Answer:

The spacing between the slits is <u>0.40233 mm</u>

Explanation:

Let 'd' be the distance between the slits and 'D' be the distance of the screen from the plane of slits.

We know that , in an interference pattern the fringe(dark or bright) width is given by -

f = \dfrac{Dλ}{d}

For 11 bright fringes , if its total spanning distance is 52.0 mm , then for one bright fringe , the fringe width(f) would be -

f = \dfrac{52}{11} = 4.72 mm

∴ From above equations ,

\dfrac{Dλ}{d} = 4.72 mm = (4.72 × 10^{-3}[/teλx]) mHere, D = 3 m           λ = 633 nm =(633 × [tex]10^{-9}) m

Substituting the values in above equation -

\dfrac{3×633×10^{-9} }{d} = 4.72 ×10^{-3}

∴ d = 0.0004023 m =0.4023 mm

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