All categories

3 years ago

2 1/5 x 2 2/3 Help me someone

Mathematics

2 answers:

prohojiy [21]3 years ago

8 0

Answer:

88/15

Step-by-step explanation:

2 1/5 * 2 2/3

{(2*5+1)/5} * {(2*3+2)/3}

11/5 * 8/3

88/15

Svetach [21]3 years ago

6 0

Given multiplication:

{2(1/5) × {2(2/3)} = {(10+1)/5} × {(6+2)/3} = (11/5)×(8/3) = {(11×8)/(5×3)} = (88/15) ≈ 5.8666...(Approximately).

also read similar questions: Multiply these fractions (Lowest Terms) a) 2 x 3/4 b) 3 x 3/5 c) 4 x 1/3 d) 6 x 2/5 e) 1/2 x 1/4 f) 4/5 x 2/3 g) 5/6 x 3/4 h ) 1/10 x 2/3 i) 2 1/5 x 1/ 2 j) 1 1...

brainly.com/question/89382?referrer

You might be interested in

Use distributive property to solve, show all steps 3(2x-6)

zlopas [31]

Answer:

6x-18

Step-by-step explanation:

First we multiply everything in the parentheses by 3

3×2x=6x

3×(-6)=-18

And now we put it together-

6x-18

4 0

3 years ago

Read 2 more answers

If 0 is in quadrant II and sin^2 0=3/4 evaluate tan0

xeze [42]

Answer:

yes. ..........................

8 0

3 years ago

If f(x) => x2 +6, what is the value of f(8)?

soldier1979 [14.2K]

Answer:22

Step-by-step explanation: since f(8) so x=8

substitiuting x in 2x+6

f(8)= 2x8+6=22

so f(8)=22

Hope this helps! :)

4 0

2 years ago

The 24 students in ms. lees class each collected an average of 18 cans for recycling. then 21 students in mr. galvez's class eac

belka [17]

This can be solve by using the average cans of each student collected and muliply it by the total students. Since for ms. Lee has 24 students and each student collected 18 cans on average, so the total can her class collected on average is 432 cans. For mr galveshas 21 students and collected 25 can per syudents on average, so the total is 525 cans. So 525 – 432 = 93 more cans the class of mr galvez collected

7 0

3 years ago

What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

Sunny_sXe [5.5K]

Answer:

First option is the correct option.

Step-by-step explanation:

$\frac{2x + 5}{ {x}^{2} - 3x } - \frac{3x + 5}{ {x}^{3} - 9x } - \frac{x + 1}{ {x}^{2} - 9 }$

Factor out X from the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x( {x}^{2} - 9)} - \frac{x + 1}{ {x}^{2} - 9}$

Using ${a}^{2} - {b}^{2} = (a - b)(a + b)$ , factor the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x(x - 3)(x + 3) } - \frac{x + 1}{(x - 3)(x + 3)}$

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

$\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}$

Multiply the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}$

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression