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arlik [135]
3 years ago
6

How many c atoms are in 2 mol of sucrose?

Chemistry
1 answer:
castortr0y [4]3 years ago
7 0
12 carbon atoms<span>, 22 hydrogen atom, and 11 oxygen atoms in 2 moles of sucrose</span>
You might be interested in
if you react 28 grams of butene with excess hydrogen how many grams of butane would you expect to get
liberstina [14]

Answer:

The correct answer is 29 grams.

Explanation:

Based on the given question, the reaction will be,

CH3CH=CHCH3 + H2 ⇒ CH3CH2CH2CH3

The molecular weight of butene is 56 grams per mole, and the molecular weight of butane is 58 grams per mole.

Thus, it can be said that 56 grams of butene reacts with hydrogen gas and produces 58 grams of butane.

Therefore, 28 grams of butene when reacts with hydrogen gas to give,

= 58/56 * 28 = 29 grams of butane.

Hence, the mass of butane produced will be 29 grams.

8 0
2 years ago
How do ions form bonds, and describe the structure of the resulting compound.​
Artemon [7]

Answer:

Electrons are transferred between atoms together in the ionic compound. The ions are arranged in a regular repeating pattern in an ionic crystal

Explanation:

6 0
2 years ago
Distinguish between accuracy and precision in measurements
nignag [31]

The accuracy is associated with magnitude of fractional error or relative error in that measurement

the precision of a measurement is associated with least count of the measuring instrument.

precision does not mean accuracy but both are highly demanded while making measurements in physics.

7 0
3 years ago
a compound has a molar mass of 129 g/mol if its empirical formula is C2H5N then what is the molecular formula
Elena-2011 [213]

Given :

A compound has a molar mass of 129 g/mol .

Empirical formula of compound is C₂H₅N .

To Find :

The molecular formula of the compound.

Solution :

Empirical mass of compound :

M_e = ( 2 \times 12 ) + ( 5 \times 1 ) + (  1  \times 14 )\\\\M_e = 43\ gram/mol

Now, n-factor is :

n = \dfrac{M}{M_e}\\\\n = \dfrac{129}{43}\\\\n = 3

Multiplying each atom in the formula by 3 , we get :

Molecular Formula, C₆H₁₅N₃

3 0
2 years ago
Why can’t you perform single displacement reactions with group IA metals?
pishuonlain [190]
Answer is: because alkaline metals (group IA metals) are the strongest reducing agents and most reactive metals.
Reducing agent<span> is an element  or compound that loses an </span>electron<span> to another </span>chemical species<span> in a </span>redox <span>chemical reaction and they have been oxidized.
Alkaline metals tend to lose only one electron in redox reaction.</span>
5 0
3 years ago
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