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Anvisha [2.4K]
3 years ago
12

What is the use of a pedigree chart? Please do not answer wat a perigee chart is!.

Chemistry
2 answers:
FinnZ [79.3K]3 years ago
8 0
Pedigree charts are used to see traits that are present in families or individuals. For example, it can be used see if certain diseases are running through someone's family and if that individual will inherit the disease.
Semmy [17]3 years ago
6 0
For animals, pedigree charts show the lineage a person may want to use for mating purposes, thus helping preserve a particular line.
You might be interested in
Using the spectra data below, which structure best matches this data? c4h8o 1h nmr triplet at 1.05 ppm (3h) singlet at 2.13 ppm
Delicious77 [7]

Answer:

Butan-2-one

Explanation:

1. 1700 cm⁻¹

A strong peak near 1700 cm⁻¹ is almost certainly a carbonyl (C=O) group.

2. Triplet-quartet

A triplet-quartet pattern indicates an ethyl group.

The 2H quartet is a CH₂ adjacent to a CH₃. The peak normally occurs at δ 1.3, but it is shifted 1.2 ppm downfield to δ 2.47 by an adjacent C=O group.

The 3H triplet at δ 1.05 is the methyl group. It, too, is shifted downfield from its normal position at δ 0.9. The effect is smaller, because the methyl group is further from the carbonyl.

3. 3H(s) at δ 2.13

This indicates a CH₃ group with no adjacent hydrogen atoms.

It is shifted 0.8 ppm downfield to δ 2.13 by the adjacent C=O group.

4. Identification

The identified pieces are CH₃CH₂-, -(CO)-, and -CH₃. There is only one way to put them together: CH₃CH₂-(C=O)-CH₃.

The compound is butan-2-one.

5 0
3 years ago
Two separate masses of zinc were measured on a laboratory balance. The first zinc had a sample mass of 210.10g, and the second z
wlad13 [49]

Answer:

Density is  7.15 g /mL.

Mass is  445.2 g.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Mass of first zinc sample = 210.10 g

Mass of second zinc sample = 235.10 g

Combined volume = 62.3 mL

Density of combined sample ?

Mass of combined sample = ?

Solution:

Mass of combined sample = 210.10 g + 235.10 g = 445.2 g

density = mass / volume

density = 445.2 g / 62.3 mL

density = 7.15 g /mL

3 0
3 years ago
Which substance is a product of a fermentation reaction?glucosezymaseethanolwater?
Makovka662 [10]
Answer is:  a product of a fermentation reaction is ethanol (C₂H₅OH).
Fermentation is a metabolic process in which ethanol is produced from sugar in the absence of oxygen (anaerobic digestion)<span>.
</span>Fermentation <span>occurs in </span>yeast, bacteria and in oxygen-starved muscle cells.
Fermentation is a way of extracting energy from molecules and it is <span>the oldest metabolic pathway.</span>
6 0
3 years ago
Compare and contrast alpha beta and gamma radiation
Evgen [1.6K]
There are usually 3 topics used to compare types of radiation: 

Ionising ability
Penetrative power 
Range in air

Ionising ability
Alpha radiation has strong ionising ability, while beta only has moderate ionisation and gamma is very weakly ionising.

Penetrative power 
Alpha particles are weakly penetrating, stopped by paper, while beta particles have stronger penetrating ability, stopped by skin and gamma radiation is very strongly penetrating, stopped only by thick layers of lead.

Range in air
Alpha particles- range of only a few centimetres
Beta - range of up to one meter 
Gamma- infinite range in air.

Hope this helps:)


8 0
3 years ago
At a certain temperature the vapor pressure of pure thiophene is measured to be . Suppose a solution is prepared by mixing of th
Lesechka [4]

Answer:

0.35 atm

Explanation:

It seems the question is incomplete. But an internet search shows me these values for the question:

" At a certain temperature the vapor pressure of pure thiophene (C₄H₄S) is measured to be 0.60 atm. Suppose a solution is prepared by mixing 137. g of thiophene and 111. g of heptane (C₇H₁₆). Calculate the partial pressure of thiophene vapor above this solution. Be sure your answer has the correct number of significant digits. Note for advanced students: you may assume the solution is ideal."

Keep in mind that if the values in your question are different, your answer will be different too. <em>However the methodology will remain the same.</em>

First we <u>calculate the moles of thiophene and heptane</u>, using their molar mass:

  • 137 g thiophene ÷ 84.14 g/mol = 1.63 moles thiophene
  • 111 g heptane ÷ 100 g/mol = 1.11 moles heptane

Total number of moles = 1.63 + 1.11 = 2.74 moles

The<u> mole fraction of thiophene</u> is:

  • 1.63 / 2.74 = 0.59

Finally, the <u>partial pressure of thiophene vapor is</u>:

Partial pressure = Mole Fraction * Vapor pressure of Pure Thiophene

  • Partial Pressure = 0.59 * 0.60 atm
  • Pp = 0.35 atm

3 0
3 years ago
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