so 96 km on 8 liters means if you divide both numbers by 8,
the car goes 12k on 1 liter of gas
now multiply both numbers by 15
180 km on 15 liters
180 km is your answer
Explanation:
In order to prove that affirmation, we define the function g over the interval [0, 1/2] with the formula 
If we evaluate g at the endpoints we have
g(0) = f(1/2)-f(0) = f(1/2) - f(1) (because f(0) = f(1))
g(1/2) = f(1) - f(1/2) = -g(0)
Since g(1/2) = -g(0), we have one chance out of three
- g(0) > 0 and g(1/2) < 0
- g(0) < 0 and g(1/2) > 0
- g(0) = g(1/2) = 0
We will prove that g has a zero on [0,1/2]. If g(0) = 0, then it is trivial. If g(0) ≠ 0, then we are in one of the first two cases, and therefore g(0) * g(1/2) < 0. Since f is continuous, so is g. Bolzano's Theorem assures that there exists c in (0,1/2) such that g(c) = 0. This proves that g has at least one zero on [0,1/2].
Let c be a 0 of g, then we have

Hence, f(c+1/2) = f(c) as we wanted.
Just multiply the 12 miles by two and the gallon by 2 to get an equivalent unit rate
24 miles per 2 gallons
Answer:
The restocking level is 113 tins.
Step-by-step explanation:
Let the random variable <em>X</em> represents the restocking level.
The average demand during the reorder period and order lead time (13 days) is, <em>μ</em> = 91 tins.
The standard deviation of demand during this same 13- day period is, <em>σ</em> = 17 tins.
The service level that is desired is, 90%.
Compute the <em>z</em>-value for 90% desired service level as follows:

*Use a <em>z</em>-table for the value.
The expression representing the restocking level is:

Compute the restocking level for a 90% desired service level as follows:


Thus, the restocking level is 113 tins.
Yes, the confidence interval provides evidence that the average has changed. The prior year’s population mean expenditure per household, $632, is not within the 95% confidence interval, (635, 663).