Answer:
decrease, increase
Step-by-step explanation:
The correct option is: Option (B)

Explanation:
First thing is that the difference between each number in the series with the next number is 5. It means it must be the multiple of 5. There are two options that contain multiples of 5: Option B and Option D. Now in the option D, the upper limit is 6. If we put 6 in the expression: 5(6)-2, the last term would be 28. However in the series given in the question, the last term is 33. Hence 5(7) - 2 = 35 - 2 = 33 which is Option B.
When i=1: 5(1)-2 = 3
When i=2: 5(2)-2 = 8
When i=3: 5(3)-2 = 13
.
.
When i=7: 5(7)-2 = 35-2 = 33
Hence the correct option is (B).
Answer 143
Explain: To find range you must Minus The Lowest Number From The Highest Out Of The Number Group
328 - 185 = Your Answer which is 143
Answer:
1) -4<x<0 = (-4,0)
2) x>=0 = [0, infinity)
3) 0<x<4 = (0,4)
4) -4<x<=4 = (-4,4]
5) x<=0 = (-infinity,0]
Step-by-step explanation:
Basically, we need to link inequalities with their solutions.
1) -4<x<0: solution to this inequality are all numbers between -4 and 0, or mathematically written (-4,0).
2) x>=0: solution to this are all numbers between 0 (including 0) and positive infinity, or [0, infinity)
3) 0<x<4: all numbers between 0 and 4, or in interval notation (0,4)
4) -4<x<=4: all numbers between -4 and 4 (including 4) which in interval notation is (-4,4]
5) x<=0: all the values from negative infinity to 0 (including 0), which is (- infinity,0]
Note that whenever there is symbol <= or >= we also need to include that value, and for noting that we use square bracket.
<u><em>I am doing this problem assuming that you mean to solve for m and n as x and y do not exist in this system of equations.</em></u>
<u><em /></u>
-4m+2n=6
-4m+n=8
We can see that the coefficient of x for both equations are -4; therefore, elimination with subtraction is possible.
<u>First equation - second equation</u>
n=-2
<u>Then substitude back in to solve for m</u>
-4m+(-2)=8
4m=10
m=5/2
Therefore the answer is
n= - 2
m= 5/2
I hope this helped and if you have any questions please ask.