Answer:
(y^2)/4 square meters
Step-by-step explanation:
For a perimeter length of x, the side of a square will be x/4 and its area will be (x/4)^2.
If one side of the square is shortened by y/2 and the adjacent side is lengthened by y/2, then the difference in side lengths will be y. The area of the resulting rectangle will be ...
(x/4 -y/2)(x/4 +y/2) = (x/4)^2 -(y/2)^2
That is, the difference in area between the square and the rectangle is ...
(x/4)^2 - ((x/4)^2 -(y/2)^2) = (y/2)^2 = y^2/4
The positive difference between the area of the square region and the area of the rectangular region is y^2/4 square meters.
Answer:
That is true!
Step-by-step explanation:
Answer:
I think the answer should be Mat A cause it has more space.
Add $35 + $55 and you get 90, multiply 90 by 5 and you get $450. so the answer is A. hope this helped.
Answer:
(a <em><u>s</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>+</u></em><em><u>7</u></em><em><u>a</u></em><em><u>+</u></em><em><u>1</u></em><em><u>2</u></em><em><u>)</u></em><em><u> </u></em><em><u>÷</u></em><em><u>(</u></em><em><u>a</u></em><em><u>+</u></em><em><u>3</u></em><em><u>)</u></em>
