Multiply (length) times (width). For a square, both numbers will be the same.
Answer:
The lemonade costs 1.4.
Step-by-step explanation:
This question is solved using a system of equations.
I am going to say that:
x is the cost of a cookie.
y is the cost of a lemonade.
Total cost for cookie and lemonade is 1.80.
This means that .
As we want y, we have that
Lemonade costs 1.00 more than the cookie?
This means that:
So
The lemonade costs 1.4.
Answer:
p = 16
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are equal, that is
= , substitute values
= ( cross- multiply )
24p = 384 ( divide both sides by 24 )
p = 16
Answer:
Correct arrangement of equation of displacement to find a is as follows;
1- Vt - d = 1/2 a t^2 (^ represents exponent i.e. t square as given in equation)
2- 2(Vt - d ) = a t^2
3- a = 2(Vt - d )/ t^2 (keep in mind, 2(Vt - d) whole divided by t^2)
Step-by-step explanation:
1- In the first equation, Vt is taken to the left side of the equation (keep in mind, original equation of displacement used for reference as given in question) and multiplied by -1 on the both sides of the equation.
2- In the second equation, 2 is multiplied on the both sides.
3- Multiply t^2 on both sides of the equation, We will get a in correct arrangement, which is required to find.
<h3><u>Answer:</u></h3>
<h3><u>Solution</u><u>:</u></h3>
we are given that , a ladder is placed against a side of building , which forms a right angled triangle . We wre given one side of a right angled triangle ( hypotenuse ) as 23 feet and the angle of elevation as 76 ° . We can find the Perpendicular distance from the top of the ladder go to the ground by using the trigonometric identity:
Here,
- hypotenuse = 23 feet
- = 76°
- Value of Sin = 0.97
- Perpendicular = ?
ㅤㅤㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>distance </u><u>from </u><u>the </u><u>top </u><u>of </u><u>the </u><u>ladder </u><u>to </u><u>the </u><u>ground </u><u>is </u><u>2</u><u>2</u><u>.</u><u>3</u><u>2</u><u> </u><u>feet </u><u>!</u>