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wariber [46]
2 years ago
14

URGENT PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST !!!

Physics
2 answers:
Levart [38]2 years ago
4 0
Visible light colors
aleksklad [387]2 years ago
4 0

Answer:

Option 2

Visible light and colors

Explanation:

Visible light has a wavelength of 380 to 740 nanometers which can be seen

by the eyes and the visible light spectrum comprises of :

Red

Orange

Yellow

Green

Blue

Indigo

Violet

U 2 can help me by marking as brainliest.......

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A string has its 4th harmonic at 31.5 Hz. What is the fundamental frequency?
seropon [69]

Given data

*The given 4th harmonic frequency is 31.5 Hz

The fundamental frequency is calculated as

\begin{gathered} f_n=\frac{31.5}{4} \\ =7.875\text{ Hz} \end{gathered}

Hence, the fundamental frequency is 7.875 Hz

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1 year ago
What is the difference between speed and velocity?
ElenaW [278]
B - speed and direction are combined in another quantity, called velocity. It can be thought of as its speed in a particular direction. Speed is the corresponding scalar quantity, because it does not have a direction.
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2 years ago
Jane has a mass of 55 kg and his body covers 700 nails with a surface area of 1.00 mm,
Oksana_A [137]

We have,

  • Jane mass is 55 kg
  • His body covered with 700 nails all of them having a surface area of 1.00 mm² each = 700 × 1 = 700 mm² = 700/1000000 = 7/10000

We know that,

  • Pressure = Force/Area

Let's calculate force as we already have area;

  • F = ma
  • F = 55 × 9.8 { Acceleration due to gravity }
  • F = 539 N

Now, if should she would be on 700 nails then pressure will be;

  • P = F/A
  • P = 539/7 × 10000
  • P = 5390000/7
  • P = 770,000 Pascal

And if should would be on a 1 nail only,

  • P = F/A
  • P = 539/1 × 1000000
  • P = 539000000 Pascal

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6 0
2 years ago
When a parachutist jumps from an airplane, he eventually reaches a constant speed, called the terminal speed. Once he has reache
Masteriza [31]

Answer:

b) True.    the force of air drag on him is equal to his weight.

Explanation:

Let us propose the solution of the problem in order to analyze the given statements.

The problem must be solved with Newton's second law.

When he jumps off the plane

     fr - w = ma

Where the friction force has some form of type.

     fr = G v + H v²

Let's replace

     (G v + H v²) - mg = m dv / dt

We can see that the friction force increases as the speed increases

At the equilibrium point

      fr - w = 0

      fr = mg

      (G v + H v2) = mg

For low speeds the quadratic depended is not important, so we can reduce the equation to

     G v = mg

     v = mg / G

This is the terminal speed.

Now let's analyze the claims

a) False is g between the friction force constant

b) True.

c) False. It is equal to the weight

d) False. In the terminal speed the acceleration is zero

e) False. The friction force is equal to the weight

3 0
3 years ago
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