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2 years ago

URGENT PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST !!!

Physics

2 answers:

Levart [38]2 years ago

4 0

Visible light colors

aleksklad [387]2 years ago

4 0

Answer:

Option 2

Visible light and colors

Explanation:

Visible light has a wavelength of 380 to 740 nanometers which can be seen

by the eyes and the visible light spectrum comprises of :

Red

Orange

Yellow

Green

Blue

Indigo

Violet

U 2 can help me by marking as brainliest.......

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3 years ago

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Two people carry a heavy object by placing it on a board that is 2.2 meters long. One person lifts with a force of 750 N at one

stiks02 [169]

Answer:

This means that the center of mass is locates 0.72m from the 750N force

Explanation:

Since the board is 2.2m long, that will be the length of the board.

Let the center of mass of the body be hinged at the center using a knife edge as shown in the diagram attached.

Let x be the distance from the 750N force to the knife edge and the distance from the 360N force to the knife edge be 2.2-x

Using the principle of moment which states that the sum of clockwise moment is equal to the sum of anti clockwise moment.

Moment = force × perpendicular distance

For ACW moment;

Moment = 750×x = 750x

For the CW moment;

Moment = 360 × (2.2-x)

Moment = 792-360x

Equating ACW moment to the clockwise moment we have;

750x = 792-360x

750x+360x = 792

1110x = 792

x = 792/1110

x = 0.72m

This means that the center of mass is locates 0.72m from the 750N force

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3 years ago

A concave mirror with a radius of curvature of 20 cm has a focal length of

xxTIMURxx [149]

Answer:

A concave mirror has a radius of curvature of 20 cm. What is it's focal length? If an object is placed 15 cm in front of it, where would the image be formed? What is it's magnification?

The focal length is of 10 cm, object distance is 30 cm and magnification is -2.

Explanation:

Given:

A concave mirror:

Radius of curvature of the mirror, as C = 20 cm

Object distance in-front of the mirror = 15 cm

Focal length:

Focal length is half of the radius of curvature.

Focal length of the mirror = $\frac{C}{2}$ = 10 cm

According to the sign convention we will put the mirror on (0,0) point, of the Cartesian coordinate open towards the negative x-axis.

Object and the focal length are also on the negative x-axis where focal length and image distance will be negative numerically.

We have to find the object distance:

Formula to be use:

⇒ $\frac{1}{focal\ length}= \frac{1}{image\ distance} + \frac{1}{object\ distance}$

⇒ Plugging the values.

⇒ $\frac{1}{-10} =\frac{1}{image\ distance}+\frac{1}{-15}$

⇒ $\frac{1}{-10} -\frac{1}{-15}=\frac{1}{image\ distance}$

⇒ $\frac{1}{-10} + \frac{1}{15}=\frac{1}{image\ distance}$

⇒ $\frac{-3+2}{30} =\frac{1}{image\ distance}$

⇒ $\frac{-1}{30} =\frac{1}{image\ distance}$

⇒ $-30\ cm=image\ distance$

Image will be formed towards negative x-axis 30 cm away from the pole.

Magnification (m) is the negative ratio of mage distance and object distance:

⇒ $m=-\frac{image\ distance}{object\ distance}$

⇒ $m=-\frac{(-30)}{(-15)}$

⇒ $m=-2$

The focal length of the concave mirror, is of 10 cm, object distance is 30 cm and magnification is -2.

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3 years ago