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Fantom [35]
2 years ago
6

Why is the linear coefficient of thermal expansion important for a restorative material?

Physics
1 answer:
iren2701 [21]2 years ago
5 0

Additionally, the coefficient of thermal expansion of the restorative material should be comparable to the coefficient of thermal expansion of the tooth structure, since a significant difference between the two could result in thermal-induced stress at the cavity wall and subsequent marginal failure.

This study's objective was to assess how thermal stress affected the marginal integrity of restorative materials with various adhesive and thermal characteristics. As an alternative to clinical trials, which are expensive and time-consuming, evaluation of restorative materials under laboratory simulations of clinical function is frequently carried out. Thermal cycling regimens, which are in vitro techniques that subject the restoration and the tooth to extremely high temperatures, are frequently used in laboratory simulations to replicate thermal stresses that naturally occur in vivo.

Learn more about Thermal Stress here-

brainly.com/question/20309377

#SPJ4

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A 175-kg motorcycle goes around an unbanked turn of radius 75.4 m at a steady 112 km/h. Determine its acceleration?
Nuetrik [128]

Answer: 12.83 m/s^{2}

Explanation:

In this case we are talking about the centripetal acceleration a_{c}, which can be calculated by:

a_{c}=\frac{V^{2}}{r}

Where:

V=112 \frac{km}{h} \frac{1000 m}{1 km} \frac{1h}{3600 s}=31.11 m/s is the speed of the motorcycle

r=75.4 m is the radius of the path the motorcycle is going around

Solving:

a_{c}=\frac{(31.11 m.s)^{2}}{75.4 m}

Finally:

a_{c}=12.83 m/s^{2}

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Jorge conducted an experiment,and included the graph shown below as part of his lab report.
victus00 [196]

The correct answer is A physical change

Explanation:

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