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mr Goodwill [35]
4 years ago
9

What is the answer for 4+90926=????? UGH SO HARD I HAVE TO GIVE IN TOMORROW

Mathematics
2 answers:
algol134 years ago
6 0
The answer is 90930.
4 + 90926= 90930
morpeh [17]4 years ago
5 0

Answer:

90930

Step-by-step explanation:


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On,Saturday, Alexa babysat her neighbors kids for 180 minutes. Then, on Sunday she babysat her little brother for 2 hours.how ma
patriot [66]

Answer:

5 hours

Step-by-step explanation:

To change minutes to hours you will have to divide the total minutes by 60 (because 60 minutes is in one hour), in this situation it would look like this:

180/60 = 3

So, Alexa babysat for 3 hours on Saturday.

Now, just add the 3 hours from Saturday and 2 hours from Sunday and you get a total of 5 hours!

<em>I hope this helps!!</em>

<em>- Kay :)</em>

8 0
3 years ago
Can Anyone Help me with this I believe I got the first one correct If not correct me please
olga_2 [115]

Answer:

the second one I think

Step-by-step explanation:

7 0
3 years ago
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Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
4 years ago
Rewrite with positive exponents a^-3 b^-5
amm1812

Answer:

1/a^3 and 1/b^5

6 0
3 years ago
What the vertex of the graph of y=-x^2
Neporo4naja [7]
First let's define vertex: A point on the curve with a local minimum or maximum of curvature. If we look for the minimum and maximum value of the equation y=x^2+5: minimum value X=0, substitute in the equation to get the maximum value of Y y = 0^2 + 5y = 0 + 5y= 5 so the ordered pair is (0,5) Hope That Helped =D
3 0
4 years ago
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