Surface area of the base = 4^2 = 16 units^2.
Area of each triangular side = 1/2 * 4 * 3 = 6 unts^2
Total surface area of the pyramid = 16 + 4 * 6 = 40 unit^2 (answer)
If it weighs 4 pounds it would be 64 Ounces
Answer:
Area is 10x^2 - 4x + 6
Step-by-step explanation:
To find this area, multiply the width and height together:
(5x^2 - 2x + 3)(2) = 10x^2 - 4x + 6
