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2 years ago

6

· Carlos ran one lap in 1 minute 3 seconds. Orlando rana one lap 5 seconds faster than Carlos. How many seconds did it take Orla

ndo to run one lap?

1 answer:

Hunter-Best [27]2 years ago

5 0

Answer:

58 seconds.

Step-by-step explanation:

Since one minute equals 60 seconds, Carlos took 63 seconds.

Orlando ran in 63 seconds - 5 seconds, which is equal to 58 seconds.

You might be interested in

Simplify the expression:<br> 3j–1+4

RUDIKE [14]

Answer:

3j/3—5/3

J=5/3

hope helps

5 0

2 years ago

To bake his favorite cake, Farrell must use 1/2 cup of water for each cup of flour. If he uses 3 1/2 cups of flour, how much wat

EastWind [94]

Answer:

The answer is 7

Step-by-step explanation:

3 1/2 ÷ 1/2 = 7

7 0

2 years ago

A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =

tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

$f(x)=-16x^2+64x+5$

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

$10=-16x^2+64x+5$

Subtracting 10 from both sides:

$-16x^2+64x-5=0$

For simplicity, divide both sides by -1:

$16x^2-64x+5=0$

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitute:

$\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}$

Evaluate:

$\displaystyle x=\frac{64\pm\sqrt{3776}}{32}$

Simplify the square root:

$\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}$

Therefore:

$\displaystyle x=\frac{64\pm8\sqrt{59}}{32}$

Simplify:

$\displaystyle x=\frac{8\pm\sqrt{59}}{4}$

Approximate:

$\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08$

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0

2 years ago

dem82 [27]

Step-by-step explanation:

1. Oblicz:

a) Liczbę o 15% mniejszą od 60

b) Liczbę, której 15% stanowi 60

c) Jakim procentem 60 jest 15

d) O ile %większa jest 60 od 15

2. Kasia kupiła buty na wyprzedaży przecenione o 20%. Ich cena początkowa to 180 zł. W domu sprzedała je siostrze zarabiając na tym 10% wartości. Ile zapłaciła Kasi siostra za buty?

3. Liczba, którą powiększymy o 20% daje nam 30. Jaka to była liczba?

4. Za dwie książki zapłacono 42 zł. Ile kosztuje droższa z nich, jeżeli jedna jest o 25 % tańsza od drugiej?

5 0

2 years ago

Helpppppppppppppppppppppp..... .......<br><br><br>

morpeh [17]

Answer:

${ \sf{( \sec \theta - \csc \theta)(1 + \tan \theta + \cot \theta) }} \\ = { \sf{( \sec \theta + \tan \theta \sec \theta + \cot \theta \sec \theta) - ( \csc \theta - \csc \theta \tan \theta - \csc \theta \cot \theta)}} \\ = { \sf{( \sec \theta + \sec \theta \tan \theta + \csc \theta) - ( \csc \theta - \sec \theta - \csc \theta \cot \theta)}} \\ = { \sf{ \sec \theta \tan \theta + \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}$

3 0

2 years ago