The term phenotype in a more specific context to describe the collective expression of the genotype in conjunction with the environment on a plant's observable characteristics.
<u>Explanation</u>:
- Phenotype, any of the measurable features of an organism arising from its genotype association (total genetic inheritance) with the environment. Behaviour, biochemical properties, colour, form, and scale are examples of measurable characteristics.
- An allele is another type of one gene. A phenotype triggered by the expression of a gene or group of genes is the external manifestation of a human trait.
- A trait is an attribute unique to an organism. The genotype's external expression is called the phénotype.
Answer:
Explanation: is that suppose to be the question or are you just saying?
Answer:
E = ρ ( R1²) / 2 ∈o R
Explanation:
Given data
two cylinders are parallel
distance = d
radial distance = R
d < (R2−R1)
to find out
Express answer in terms of the variables ρE, R1, R2, R3, d, R, and constants
solution
we have two parallel cylinders
so area is 2
R × l
and we apply here gauss law that is
EA = Q(enclosed) / ∈o ......1
so first we find Q(enclosed) = ρ Volume
Q(enclosed) = ρ (
R1² × l )
so put all value in equation 1
we get
EA = Q(enclosed) / ∈o
E(2
R × l) = ρ (
R1² × l ) / ∈o
so
E = ρ ( R1²) / 2 ∈o R
Answer:
Temperature of the hot reservoir is 1540K
Explanation:
![E= 1- \frac{T_{c}}[tex]{T_h}=308+{T_c}\\Efficiency of a carnot engine is given by the aboveTc=temperature of the cold reservoirTh= temperature of the hot reservoirK=273+ 35 (convert 35°C to kelvin)K=308k{T_h}={T_c}+308-----------------------(equation 1)20%=1-{T_c}/{T_h}](https://tex.z-dn.net/?f=E%3D%201-%20%5Cfrac%7BT_%7Bc%7D%7D%5Btex%5D%7BT_h%7D%3D308%2B%7BT_c%7D%5C%5C%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EEfficiency%20of%20a%20carnot%20engine%20is%20given%20by%20the%20above%3C%2Fp%3E%3Cp%3ETc%3Dtemperature%20of%20the%20cold%20reservoir%3C%2Fp%3E%3Cp%3ETh%3D%20temperature%20of%20the%20hot%20reservoir%3C%2Fp%3E%3Cp%3EK%3D273%2B%2035%20%20%28convert%20%2035%C2%B0C%20to%20kelvin%29%3C%2Fp%3E%3Cp%3EK%3D308k%3C%2Fp%3E%3Cp%3E%3Cstrong%3E%7BT_h%7D%3D%7BT_c%7D%2B308-----------------------%28equation%20%201%29%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3E20%25%3D1-%7BT_c%7D%2F%7BT_h%7D)
0.2=({T_c}+308-{T_c})/{T_c}+308
.2({T_c}+61.6=308
0.2{T_c}=246.4
{T_c}=1232
recall from equation 1
{T_h}=308+1232
{T_h}=1540K