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Inga [223]
3 years ago
7

A helicopter hovers 568 m above a field and 96 kJ of gravitational potential

Physics
1 answer:
kkurt [141]3 years ago
3 0

Answer:

mass m = 17.2 kg.

Explanation:

Use potential energy =m*g*h,

so,

m=potential energy/(g*h)

m=96000 J/(9.8*568) = 17.2 kg

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What are some of the phenotypic plant traits that scientists are investigating? Why do you think these traits were chosen?
vodomira [7]

The term phenotype in a more specific context to describe the collective expression of the genotype in conjunction with the environment on a plant's observable characteristics.

<u>Explanation</u>:

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3 years ago
A space station worker found herself floating free 100 meters from the space station because her safety line became unhooked
yuradex [85]

Answer:

Explanation: is that suppose to be the question or are you just saying?

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3 years ago
If the axes of the two cylinders are parallel, but displaced from each other by a distance d, determine the resulting electric f
Novay_Z [31]

Answer:

E =  ρ ( R1²) / 2 ∈o R

Explanation:

Given data

two cylinders are parallel

distance = d

radial distance = R

d < (R2−R1)

to find out

Express answer in terms of the variables ρE, R1, R2, R3, d, R, and constants

solution

we have two parallel cylinders

so area is 2 \pi R × l

and we apply here gauss law that is

EA = Q(enclosed) / ∈o   ......1

so first we find  Q(enclosed) = ρ Volume

Q(enclosed) = ρ ( \pi R1² × l )

so put all value in equation 1

we get

EA = Q(enclosed) / ∈o

E(2 \pi R × l)  = ρ ( \pi R1² × l ) / ∈o

so

E =  ρ ( R1²) / 2 ∈o R

6 0
3 years ago
The Han Dynasty is best described as a:
inna [77]
Territory and nation
5 0
4 years ago
For a certain ideal Carnot engine, the hot reservoir is 35°C higher than the cold reservoir. If this engine is to have an effici
lord [1]

Answer:

Temperature of the hot reservoir is 1540K

Explanation:

E= 1- \frac{T_{c}}[tex]{T_h}=308+{T_c}\\Efficiency of a carnot engine is given by the aboveTc=temperature of the cold reservoirTh= temperature of the hot reservoirK=273+ 35  (convert  35°C to kelvin)K=308k{T_h}={T_c}+308-----------------------(equation  1)20%=1-{T_c}/{T_h}

0.2=({T_c}+308-{T_c})/{T_c}+308

.2({T_c}+61.6=308

0.2{T_c}=246.4

{T_c}=1232

recall from equation 1

{T_h}=308+1232

{T_h}=1540K

5 0
3 years ago
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