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Kisachek [45]
4 years ago
15

Consider two metallic rods mounted on insulated supports. One is neutral, the other positively charged. You bring the two rods c

lose to each, but without contact, and briefly ground the the neutral rod by touching it with your hand. show answer Correct Answer What would be resulting charge (if any) on the initially neutral rod
Physics
1 answer:
EastWind [94]4 years ago
3 0

Answer:

I think it will be half of the initial charge

Explanation:

Because we know, the resulting charge will be q1+q2/2, since one is neutral so the charge will be half q/2

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24. A total of 165 J of work is done on a gaseous refrigerant as it undergoes compression. If the internal energy of the gas inc
Yuliya22 [10]

The total amount of energy transferred as heat is equal to 288 Joules.

<u>Given the following data:</u>

  • Internal energy = 123 Joules
  • Work done = 165 Joules

To calculate the total amount of energy transferred as heat, we would apply the first law of thermodynamics.​

<h3>The first law of thermodynamics.</h3>

Mathematically, the first law of thermodynamics is given by the formula:

\Delta E = Q - W

<u>Where;</u>

  • \Delta E is the change in internal energy.
  • Q is the quantity of heat transferred.
  • W is the work done.

Substituting the given parameters into the formula, we have;

123 = Q - 165\\\\Q=123+165

Q = 288 Joules.

Read more on internal energy here: brainly.com/question/25737117

4 0
3 years ago
How much KCI can be dissolved in 100 g of water at 30°C?​
asambeis [7]

Answer:

34

Explanation:

The problem provides you with thesolubility of potassium chloride, KCl , in water at 20∘C , which is said to be equal to 34 g / 100 g H2O . This means that at 20∘C , a saturated solution of potassium chloride will contain 34 g of dissolved salt for every100 g of water.

6 0
3 years ago
Read 2 more answers
1. 3 main components of a circuit
siniylev [52]
Voltage, resistance and current are the three components that must be present for a circuit to exist. A circuit will not be able to function without these three components. Voltage is the main electrical source that is present in a circuit. :)
7 0
3 years ago
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A bowling ball of mass 4 kg moves in a straight line at 3.93 m/s. How fast must a Ping-Pong ball of mass 2.293 g move in a strai
Nonamiya [84]

M = mass of the bowling ball = 4 kg

V = speed of bowling ball = 3.93 m/s

P = magnitude of momentum of bowling ball = ?

magnitude of momentum of bowling ball is given as

P = MV

inserting the values

P = 4 x 3.93

P = 15.72 kgm/s

m = mass of ping-pong ball = 2.293 g = 2.293 x 10⁻³ kg

v = speed of the ping-pong ball = ?

p = magnitude of momentum of ping-pong ball

Given that :

magnitude of momentum of ping-pong ball  =  magnitude of momentum of bowling ball

p = P

m v = 15.72

(2.293 x 10⁻³) v = 15.72

v = 6.86 x 10³ m/s


4 0
3 years ago
A stone is dropped into a river from a bridge at a height h above the water. Another stone is thrown vertically down at a time t
Mumz [18]

Answer:

v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}

Explanation:

We will apply the equations of kinematics to both stones separately.

First stone:

Let us denote the time spent after the second stone is thrown as 'T'.

y - y_0 = v_{y_0}(t+T) + \frac{1}{2}a(t+T)^2\\0 - h = 0 + \frac{1}{2}(-g)(t+T)^2\\(t+T)^2 = \frac{2h}{g}\\T = \sqrt{\frac{2h}{g}}-t

Second stone:

y - y_0 = v_{y_0}T + \frac{1}{2}aT^2\\0 - h = v_{y_0}T -\frac{1}{2}gT^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\sqrt{\frac{2h}{g}} - t)^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\frac{2h}{g} + t^2 - 2t\sqrt{\frac{2h}{g}})\\-h = v_{y_0}\sqrt{\frac{2h}{g}} - v_{y_0}t - h -\frac{g}{2}t^2 + gt\sqrt{\frac{2h}{g}}\\v_{y_0}(\sqrt{\frac{2h}{g}} - t) = \frac{g}{2}t^2 - gt\sqrt{\frac{2h}{g}}\\v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}

6 0
3 years ago
Read 2 more answers
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