Light is a form of what

A typical wind turbine extracts 40% of the kinetic energy of the wind that blows through the area swept by the blades. For a lar

chubhunter [2.5K]

Answer:

2.9744 MW

Explanation:

The air blowing through the wind turbine at 110000kg at speed of 13m/s for every second would have the kinetic energy of

$E_k = 0.5mv^2 = 0.5*110000*13^2 = 9295000J/s$

If the wind turbine is able to extract only 40% of this kinetic energy, and 80% of this is converted to electricity, then the power output of the generator must be

$E = 80\%*40\%*E_k = 0.8*0.4*9295000= 2974400J/s$

or 2.9744 MegaWatt

4 0

3 years ago

A box is released from rest and allowed to slide down a ramp with friction. Which statement most accurately describes the energy

jek_recluse [69]

Answer:

d) The box’s initial potential energy is transformed into kinetic energy and

thermal energy.

Explanation:

Let us analyze the situation first. Initially we have a box at rest placed at some height on a ramp. So, the three energies associated with the box will be:

Kinetic Energy = 0 (due to zero velocity)

Thermal Energy = 0 (due to not temperature change)

Potential Energy = Greater than zero value (due to height)

Now, when the box is released to slide down the ramp with friction, the energies become:

Kinetic Energy = Increasing (due to increase in velocity)

Thermal Energy = Increasing (due to increase in temperature, because of friction)

Potential Energy = Decreasing (due to decrease in height)

So, from Law of Conservation of Energy, we can write:

Loss of Potential Energy = Gain in Kinetic Energy + Gain in Thermal Energy

So, the correct option is:

d) The box’s initial potential energy is transformed into kinetic energy and thermal energy.

5 0

3 years ago

"A uniform cylinder of mass M and radius R is rolling without slipping. The velocity of its center of mass is v. What is the cyl

Goshia [24]

Answer:

Explanation:

Given

mass of cylinder is M

radius R

velocity of center of mass is v

As there is no slipping therefore cylinder will rotate as well as translate

Moment of inertia of cylinder $I=\frac{MR^2}{2}$

Kinetic Energy of cylinder $K.E.=\frac{1}{2}Mv^2$

Rotational energy $R.E.=\frac{1}{2}I\omega ^2$

for rolling

$v=\omega \times r$

where $\omega =angular\ velocity\ of\ cylinder$

$R.E.=\frac{1}{2}\times \frac{MR^2}{2}\times (\frac{v}{R})^2=\frac{1}{4}Mv^2$

Total kinetic Energy $=\frac{1}{2}Mv^2+\frac{1}{4}Mv^2=\frac{3}{4}Mv^2$

6 0

3 years ago

Kevin decides to soup up his car by replacing the car's wheels with ones that have 1.4 times the diameter of the original wheels

True [87]

Answer:

No.

Explanation:

Given that Kevin decides to soup up his car by replacing the car's wheels with ones that have 1.4 times the diameter of the original wheels. Note that the speedometer in a car is calibrated based on the tire's diameter and on the distance the tire covers in each revolution. (a) Will the reading of the speedometer change ?

Considering the formula

V = wr

Where

V = linear speed

W = angular speed

r = radius of the wheel.

But W = 2πrf

Where the the 2 and pi are constant. The radius of the first wheel will be small but counter balance with the larger frequency.

While the radius of the second wheel may be large but it will be of a small frequency.

We can therefore conclude that the reading on the speedometer will not change. Because speedometer will read the linear speed V.

7 0

2 years ago

URGENT Find the total equivalent resistance for the circuit.

Nesterboy [21]

Answer:

$20 + 10 = 30 \\ 30and50 in \: parallel \\ = \frac{50 \times 30}{50 + 30} \\ = \frac{1500}{80} \\ 18.75 \\ 30nd40parallel \\ \frac{30 \times 40}{70} \\ \frac{1200}{70} = 17.143 \\ total = 18.75 + 17.143 = 35.893ohm \\ thank \: u$

3 0

2 years ago