Well, the lines of workings are cut off in the middle, and there's no 2nd image.
But I think it must have to do with the "cos" terms at the right end of the picture.
I'm guessing now, because the part I'm interested in would be just past the edge, where we can't see it.
I <em>think</em> that the first line says "cos(some angle)", and at the same place in the second line it says "cos(180 - the same angle)".
If that's what it says, then that's your answer, because cos(anything) is equal to the <em>negative</em> of cos(180 - the same thing).
That's the best I can do for you just now. Honestly, I don't see the connection yet between the question Dave is working on and the two lines I see in the picture.
Answer:— A square labeled Object B is shown with an arrow pointing up labeled 3 N, an arrow pointing right labeled 2 N, an arrow pointing down labeled 3 N and an arrow pointing left labeled 1 N. In which direction will the objects move? Object A will move down and Object B will move up.
Explanation:
Its fake some of its real like the space part and the traveling through space part but not the multi dimensional stuff
ANSWER:
a)Angle = 79°
b)Resultant vector = 10.2m/s
a)Use the pythagoras trigonometry ratios to obtain the angle..,
Vertical(opposite) = 10
Horizontal(adjacent) = 2
tan theta = 10/2...,where theta is representing the angle.
;theta = 79°
b) Resultant vector(R)...we use the pythagoras to calculate it,
Where our resultant vector is the hypothenus...,
R^2 = 10^2 + 2^2
R^2 = 104
Hence,
;Resultant vector = square root of 104
= 10.2 m/s
Answer:
∆L=aL∆T
Explanation:
that's the answer for your Question