1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zina [86]
3 years ago
15

Which statement about two objects having the same momentum is true?

Physics
1 answer:
Reil [10]3 years ago
7 0

Answer:

The product of mass X velocity is the same for both

Explanation:

The momentum of a body is the product of its mass and velocity.

  Momentum  = mass x velocity

Two objects having equal momentum will have the same for the product of their mass and velocity.

  • It is amount of motion a body can produce.
You might be interested in
Kinetic Energy - What does it depend on?
Greeley [361]

Answer:

faster; more kinetic energy

Explanation:

7 0
2 years ago
A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk at its center. Rotating flywheels provid
Sergeeva-Olga [200]

Answer:

8.37*10^5 rpm

Explanation:

Given that rotational kinetic energy = 4.66*10^9J

Mass of the fly wheel (m) = 19.7 kg

Radius of the fly wheel (r) = 0.351 m

Moment of inertia (I) = \frac{1}{2} mr ^2

Rotational K.E is illustrated as (K.E)_{rt} = \frac{1}{2} I \omega^2

\omega = \sqrt{\frac{2(K.E)_{rt}}{I} }

\omega = \sqrt{\frac{2(KE)_{rt}}{1/2 mr^2} }

\omega = \sqrt{\frac{4(K.E)_{rt}}{mr^2} }

\omega = \sqrt{\frac{4*4.66*10^9J}{19.7kg*(0.351)^2} }

\omega = 87636.04

\omega = 8.76*10^4 rad/s

Since 1 rpm = \frac{2 \pi}{60}  rad/s

\omega = 8.76*10^4(\frac{60}{2 \pi})

\omega = 836518.38

\omega = 8.37 *10^5 rpm

3 0
3 years ago
What has research determined about the orbit of an electron around a nucleus?
sergeinik [125]
The one that research has determined about the orbit of an electron around nucleus is : Each sub-level electron type has a unique path where it will likely to be found
Here are the sub levels of an electron :
-sub level s, maximum number of 2 electrons
- sub level p, maximum number of 6 electrons
- sub level d, maximum number of 10 electrons
- sub level f, maximum number of 14 electrons
8 0
3 years ago
Read 2 more answers
If velocity is in m/s and time is in sec, what is the unit of acceleration?​
WINSTONCH [101]
The unit of acceleration would be m/s² :)
6 0
2 years ago
On a horizontal frictionless surface, a small block with mass 0.200 kg has a collision with a block of mass 0.400 kg. Immediatel
Akimi4 [234]

Answer:48.2 Joules

Explanation:

Given

two masses of 0.2 kg and 0.4 kg collide with each other

after collision 0.2 kg deflect 30 north of east and 0.4 kg deflects 53.1 south of east

Velocity of 0.2 kg mass is

v_{0.2}=12\cos (30)\hat{i}+12\sin (30)\hat{j}

|v_{0.2}|=11.99 m/s\approx 12 m/s

Velocity of 0.4 kg mass

v_{0.4}=13\cos (53.1)\hat{i}-12\sin (53.1)\hat{j}

|v_{0.4}|=12.99 m/s\approx 13 m/s

Thus total Kinetic energy =\frac{0.2\times 12^2}{2}+\frac{0.4\times 13^2}{2}

Kinetic energy=48.2 J

8 0
3 years ago
Other questions:
  • Which process is a physical change?
    5·1 answer
  • A train consists of 50 cars, each of which has a mass 6.8
    8·1 answer
  • Which point lies on the line with point slope equation : y+5=2(x+8)
    9·2 answers
  • When are the two days of equinox
    11·2 answers
  • A man pulls a wagon with a handle that is at an angle of 42° with the ground. If the man pulls with 330 N of force, how much for
    9·2 answers
  • HELP PLZ QUICK HELP PLZ QUICK HELP PLZ QUICK HELP PLZ QUICK
    7·2 answers
  • A 12,500 kg railroad freight car travels on a level track at a speed of 5.2 m/s. It collides and couples with a 22,600 kg second
    8·1 answer
  • The amount of air resistance acting on an object depends on the objects
    15·1 answer
  • Why is it so hot along the equator?
    14·2 answers
  • Metals are used in many products because of the characteristic properties that most metals have.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!