N=3.5 mol
c=3.5 mol/L
n=cv
v=n/c
v=3.5/3.5=1.0 L
A) 1.0 liter of solution
Explanation:
![ClO^-(aq)+H_2O(l) \rightarrow HClO (aq)+OH^-(aq)\ [fast]](https://tex.z-dn.net/?f=ClO%5E-%28aq%29%2BH_2O%28l%29%20%5Crightarrow%20HClO%20%28aq%29%2BOH%5E-%28aq%29%5C%20%5Bfast%5D)
![I^-(aq)+HClO(aq) \rightarrow HIO(aq)+Cl^-(aq)\ [slow]](https://tex.z-dn.net/?f=I%5E-%28aq%29%2BHClO%28aq%29%20%5Crightarrow%20HIO%28aq%29%2BCl%5E-%28aq%29%5C%20%5Bslow%5D)
![OH^-(aq)+HIO(aq) \rightarrow H_2O(l)+IO^-(aq)\ [fast]](https://tex.z-dn.net/?f=OH%5E-%28aq%29%2BHIO%28aq%29%20%5Crightarrow%20H_2O%28l%29%2BIO%5E-%28aq%29%5C%20%5Bfast%5D)
(a)
Cancelling common terms, the overall reaction is as follows:
![ClO^-(aq)+I^-(aq) \rightarrow Cl^- (aq)+IO^-(aq)](https://tex.z-dn.net/?f=ClO%5E-%28aq%29%2BI%5E-%28aq%29%20%5Crightarrow%20Cl%5E-%20%28aq%29%2BIO%5E-%28aq%29)
(b)
Chemical species which are generated and consumed during the reaction are called intermediates. Therefore, in the given reaction, HClO(aq), OH-(aq) and HIO(aq) are intermediate species.
(c)
two reactant molecules are involved in each steps, therefore, each steps are bimolecular. Since water is in excess, therefore will not be rate law
Rate law for first step:
![rate=k_1[ClO^-]](https://tex.z-dn.net/?f=rate%3Dk_1%5BClO%5E-%5D)
Rate law for second step:
![rate=k_2 [I^-][HClO]](https://tex.z-dn.net/?f=rate%3Dk_2%20%5BI%5E-%5D%5BHClO%5D)
Rate law for third step:
![rate=k_3[OH^-][HIO]](https://tex.z-dn.net/?f=rate%3Dk_3%5BOH%5E-%5D%5BHIO%5D)
(d)
Step 2 is slow step, therefore this step will be rate determining step.
So, rate = k [I-] [HClO]
So, it consisted with the actual rate law
Answer:
correct substrate to bind the active site of the enzyme.
Explanation:
For an enzyme to catalyze a chemical reaction it is very essential for the correct substrate to bind the active site of the enzyme.
The Active site consists of two parts
1.Binding site
2. Catalytic site
The binding site consists of amino acid residues that bind to the correct substrate while the catalytic site has the amino acids that lead to the catalysis.
The active site's shape is such that only the right substratum easily binds to it and thus the catalytic reaction occurs.
Barium :
![Ba^{+2}](https://tex.z-dn.net/?f=Ba%5E%7B%2B2%7D%20)
with +2 being the charge
Oxygen :
![O^{-2}](https://tex.z-dn.net/?f=O%5E%7B-2%7D%20)
with -2 being the charge
The given equation can be written as:
Ba + O = BaO
Since the sum charges of Barium and Oxygen equals 0, there is no need to add subscripts.
Both Ba and O appear on the left and right side of the equation once, so there is no need to add a coefficient.
Ba + O = BaO is balanced
46. F the mouth.
Because the mouth works as the food smasher and with the addition of saliva the food will be softer to digest.
47. D The Weight
Because weight is mass times the acceleration of gravity and acceleration of gravity is different on moon 1.620 m/s^2.
48.G Two elements
Because compounds are made of two or more than two elements.