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Answer:
We need 41.2 L of propane
Explanation:
Step 1: Data given
volume of H2O = 165 L
Step 2: The balanced equation
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
Step 3: Calculate moles of H2O
1 mol = 22.4 L
165 L = 7.37 moles
Step 4: Calculate moles of propane
For 1 mol C3H8 we need 5 moles O2 to produce 3 moles CO2 and 4 moles H2O
For 7.37 moles H2O we need 7.37/4 = 1.84 moles propane
Step 5: Calculate volume of propane
1 mol = 22.4 L
1.84 moles = 41.2 L
We need 41.2 L of propane
Answer:
The rate of reaction increases when the reaction is catalyzed by using catalyst.
Explanation:
Catalyst is a specie which when involved in reaction, speeds up the reaction without consuming itself. The catalyst is regenerated at the end of reaction and is recovered in good yield. Catalyst main role in reaction is to decrease the Activation energy of the reaction. This decrease in activation is achieved through different mechanisms. Without going in detail, they are as follow,
1) By providing different pathway to reaction
2) By weakening the bonds
3) By providing surface area to reactants
