Answer:
19.28 g/cm^3 to the nearest hundredth.
Explanation:
The volume of water displaced = the volume of the metal.
density = mass / volume
0.0694 kg = 0.0694 * 1000
= 69.4 g.
Density = 69.4 / 3.6
= 19.28 g/cm^3.
In order to write a balanced equation, all you have to do is look at your atoms on each side and make sure there are the same amount present on either side.
K 1 | K 1
OH 1 | OH 3
Al 1 | Al 1
NO3 3 | NO3 1
So what you would need to do is add a coefficient in front of each compound to make sure there is the same amounts on either side. Your equation should look like this at the end:
3KOH(aq) + Al(NO3)3(aq) —-> Al(OH)3(s) + 3KNO3(aq)
Make sure that when you are balancing you keep the polyatomic ions together.
According to Avogadro's law, the two gases will have equal number of molecules.
<h3>Avogadro's law </h3>
From the question, we are to determine how the two gases would compare according to Avogadro's law
First, we will state the Avogadro's law
<em>Avogadro's law</em> states that "equal volume of all gases at the <u>same temperature and pressure</u> contain the same number of molecules"
Now, from the given information
We have 2 liters of hydrogen gas and 2 liters of oxygen gas at the <u>same temperature and pressure</u>
According to Avogadro's law, gases that are equal in volume and are at the same temperature and pressure will have equal number of molecules.
Hence, according to Avogadro's law, the two gases will have equal number of molecules.
Learn more on Avogadro's law here: brainly.com/question/26174006
Answer:
is this a question? or...
1) We know that rtp = number of moles × 24
= 0.25 × 24
= 6 dm³
Therefore the volume of 0.25 moles of gas at rtp is A) 6 dm³
3.1) Amount of Copper = 20 tonnes
Amount of pure copper from impure copper = 18 tonnes
Purity of copper = (Pure copper/ impure copper) × 100
= (18 / 20) × 100
= 18 × 5
= 90 %
Therefore the purity of copper is 90%
3.2) We know that oxygen has 8 protons and 8 neutrons, so the weight of oxygen molecule is 8 + 8 = 16 u
So, one mole of oxygen weighs 16 g, so 2 moles weigh 2 × 16 = 32 grams
But oxygen is diatomic so the weight is 32 × 2 = 64 grams
Therefore the weight of 2 moles of oxygen is 64 grams
3.3) Concentration of solution = Amount of solute/volume
= 4 moles/ 2 dm³
= 4 / 2
= 2 mol/dm³
Therefore the concentration of a solution containing 4 moles in 2 dm³ of solution is 2 mol/dm³
Happy to help :)
If you need any more help, fell free to ask
Extremely sorry for the late answer
