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snow_lady [41]
3 years ago
8

assume you have a 500 g sample of a radioactive isotope with a half-life of 100 years. fill in the table showing how many grams

of material will remain after the indicated time has passed.
Chemistry
2 answers:
djverab [1.8K]3 years ago
6 0
8.10 hours is the answer
sweet-ann [11.9K]3 years ago
3 0

Answer:

8.10 hours.

Explanation:

You start with 500.0g.

After the first half-life, you have 250.0g.

After the second, you have 125.0g.

After the third, you have 62.50g.

Therefore, it takes three half-lives to decay to 62.50g.

Therefore, the elapsed time must be triple the length of one half-life.

24.3

3

=

8.10

, so it is 8.10 hours.

Explanation:

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12345 [234]

Answer:

<em>Dentro de las aplicaciones de la óxido-reducción se pueden encontrar:</em>

  1. <u><em>La obtención del aluminio a partir de la alúmina y la electrolisis.</em></u>
  2. <u><em>La obtención de cloro, hidrógeno e hidróxido de sodio a partir del cloruro de sodio y la electrolisis.</em></u>
  3. <u><em>La combustión interna de un motor a gasolina u otro combustible fósil.</em></u>
  4. <u><em>Las termoeléctricas, las cuales para generar energía realizan combustión de carbón.</em></u>
  5. <u><em>La galvanoplastia, donde para evitar la corrosión de un metal se recubre con otro metal más resistente, por ejemplo: el recubrimiento del acero con zinc.</em></u>
  6. <u><em>La pilas o baterías de las cuales se obtiene energía química</em></u><em>.</em>

Explanation:

<em>Como puedes ver en la respuesta, la óxido-reducción tiene diversas aplicaciones en la vida moderna, desde todos los tipos de combustión los cuales sirven para brindar energía o movilizarte, hasta todas las funciones que se le ha dado a la electrolisis y a la obtención de la energía por medios químicos, incluso se puede considerar una aplicación de la óxido-reducción la incorporación de antioxidantes en los alimentos, los cuales disminuyen la velocidad de descomposición de los mismos. </em>

3 0
3 years ago
While working near a radioactive mine, workers usually wear heavy plastic suits. These suits protect them from all but
Vaselesa [24]
The appropriate response is gamma radiation. Alpha particles can be halted via air. UV radiation can be halted by a typical layer of clothing.Beta particles can be ceased by the thick plastic suit. Just gamma radiation can enter the substantial suit. It must be halted by thick dividers of lead or cement.
4 0
3 years ago
Read 2 more answers
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saw5 [17]

Explanation:

Percentage composition = 2/18 = 11.11%.

5 0
3 years ago
20 points - Chemistry - plzzz help
Angelina_Jolie [31]

Answer:

1. Inversely proportional

2. Option C. Boyle's Law

3. Directly proportional

4. Option C. Gay-Lussac's Law

5. Directly proportional

6. Option C. Charles' Law

Explanation

Boyle's law states that the volume of a fixed mass of gas is inversely proportional to the pressure provided temperature remains constant. Mathematically,

V & 1/P

V = K/P

PV = K(constant)

Charles' law states that the volume of a fixed mass of gas is directly proportional to it's absolute temperature, provided pressure remains constant. Mathematically,

V & T

V = KT

V / T = K(constant)

Gay-Lussac's Law states that the pressure of a fixed mass of gas is directly proportional to it's absolute temperature, provided the volume remains constant. Mathematically

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7 0
3 years ago
ODIO POD
miss Akunina [59]

Answer:

\boxed{\text{40 mol Al}}

Explanation:

            Al₂O₃ ⟶ 2Al + 3O₂

n/mol:     20

\text{Moles of Al} = \text{20 mol Al$_{2}$O$_{3}$}\times \dfrac{\text{2 mol Al}}{\text{1 mol Al$_{2}$O$_{3}$}}= \textbf{40 mol Al}\\\text{You can produce }\boxed{\textbf{40 mol Al}}

8 0
3 years ago
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