Answer:
First we know that the molar mass of CO2 is 44.01g/mol, and that the sample of CO2 contains 3.408 x 10^21 molecules, and we have to find the mass of that sample.
We know that moles = mass/molar mass, if we rearrange the equation for mass, we'll get:
mass = moles x molar mass
Also, note that the number of atoms/molecules in a sample is the moles of the sample x Avogadro's number (6.02 x 10^23)
If we rearrange the equation for moles, we would get:
moles = molecules of sample/6.02 x 10^23
Plug in the values for the equation above to get the moles:
moles = (3.408 x 10^21)/(6.02 x 10^23)
moles = 0.00566112956 (we're not done yet)
Now that we have the moles and we were already provided the molar mass, we can calculate the mass using the very first equation we rearranged.
mass = moles x molar mass
mass = 0.00566112956 x 44.01
mass = 0.2491g (answered 4 places past the decimal point<u>)</u>
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<u>Therefore the sample of Carbon Dioxide has a mass of 0.2491g</u>
Answer:
I have no idea how to do this question its hard for me
Explanation:
What is the exoeruent. Searched it up on google and only came up with two search results. None related to chemistry
Answer:
a) But-1-ene
b) E-But-2-ene
c) Z-But-2-ene
d) 2-Methylpropene
Explanation:
In this case, if we want to draw the <u>isomers</u>, we have to check the<u> formula </u>
in this formula we can start with a linear structure with 4 carbons. We also know that we have a double bond, so we can put this double bond between carbons 1 and 2 and we will obtain <u>But-1-ene.</u>
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For the next isomer, we can move the double bond to carbons 2 and 3. When we do this can have two structures. When the methyl groups are placed on the same side we will obtain <u>Z-But-2-ene</u>. When the methyls groups are placed on opposite sides we will obtain <u>E-But-2-ene.</u>
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Finally, we can use a linear structure of three carbons with a methyl group in the middle with a double bond, and we will obtain <u>2-Methylpropene.</u>
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See figure 1 to further explanations.
I hope it helps!
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