According to the law of conservation of mass, the total mass of the reacting substances is

Chemistry

1 answer:

atroni [7]3 years ago

7 0

Answer:

I would say the last one because mass is not created nor destroyed.

Explanation:

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On a planet where the temperature is so high, the ground state of an electron in the hydrogen atom is n = 4. What is the ratio o

kvv77 [185]

Answer:

1:16

Explanation:

The ground state of an electron on the planet is n = 4 compared the ground state of an electron at n =1. For a hydrogen atom, the electron energy level is given as:

$E(n)=\frac{13.6}{n^2}\\ \\Where\ n\ is\ the\ ionization \ energy$

$E(4)=\frac{13.6}{4^2}=\frac{13.6}{16}\\ \\E(1)=\frac{13.6}{1^2}=\frac{13.6}{1}\\ \\The\ ratio\ of\ their\ ionization\ energy=\frac{E(4)}{E(1)} =\frac{\frac{13.6}{16} }{\frac{13.6}{1} } =\frac{1}{16}=1:16$

Hence the ratio of their ionization energies is 1:16

6 0

4 years ago

Bromo-4-fluorohexane has two chiral carbon atoms; therefore, the maximum number of possible stereoisomers that can be formed is

Zepler [3.9K]

Here we have to draw the four isomers of the compound 3-bromo-4-fluorohexane.

The four isomers of the compound is shown in the figure.

In an organic molecule the chiral -C center is that where four (4) different groups are present. In 3-bromo-4-fluorohexane the 3 and 4 positions are chiral centers. The possible isomers of a molecule can be obtained from the formula 2n. As here 2 chiral centers are present thus number of stereoisomers will be 2×2 = 4.

The four different isomers as shown in the figure are 3R-, 4R-; 3S-, 4S; 3R, 4S and 3S-, 4R- 3-bromo-4-fluorohexane.

In the 3-bromo-4-fluorohexane the functional groups are -Br, C₂H₅, -C₃H₆F and -H for 3-position and -F, -C₂H₅, -C₃H₆ and -H for 4-position respectively.

The priority of the -3 position will be Br > C₃H₆F > C₂H₅ > H and for -4 position F > C₃H₆Br > C₂H₅ > H. If the rotation from the higher priority group to lower is clockwise and anticlockwise then the S- and R- notation are used respectively. However if the -H atom is present at the horizontal position then the notation will be reverse.

Thus the four isomers of the compound is shown.