The 15th term in the given A.P. sequence is a₁₅ = 33.
According to the statement
we have given that the A.P. Series with the a = 5 and the d is 2.
And we have to find the 15th term of the sequence.
So, for this purpose we know that the
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
And the formula is a
an = a + (n-1)d
After substitute the values in it the equation become
an = 5 + (15-1)2
a₁₅ = 5 + 28
Now the 15th term is a₁₅ = 33.
So, The 15th term in the given A.P. sequence is a₁₅ = 33.
Learn more about arithmetic progression here
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Answer:
0.44
Step-by-step explanation:
-3x^2 + 2y^2 + 5xy - 2y +5x^2 - 3y^2
Combine like terms
-3x^2 + 5x^2 = 2x^2 2y^2 - 3y^2 = -1y^2
2x^2 - 1y^2 + 5xy - 2y
Now plug in the solutions Note: it is easier if you have all decimals or all fractions (-1/10=-.1
2(0.5)^2 - 1(-0.1)^2 + 5(0.5)(-0.1) - 2(-0.1)
Simplify:
0.5 - 0.01 - 0.25 + 0.2
0.5 + 0.2 - 0.01 - 0.25
0.7 - 0.26
0.44
The answer is probably 590,000 because isn't it subtraction
AD > EC
the 25° angle is more inclined than the other
Answer:
x = -7/40
, y = -11/20
Step-by-step explanation:
Solve the following system:
{12 x - 2 y = -1 | (equation 1)
4 x + 6 y = -4 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{12 x - 2 y = -1 | (equation 1)
0 x+(20 y)/3 = (-11)/3 | (equation 2)
Multiply equation 2 by 3:
{12 x - 2 y = -1 | (equation 1)
0 x+20 y = -11 | (equation 2)
Divide equation 2 by 20:
{12 x - 2 y = -1 | (equation 1)
0 x+y = (-11)/20 | (equation 2)
Add 2 × (equation 2) to equation 1:
{12 x+0 y = (-21)/10 | (equation 1)
0 x+y = -11/20 | (equation 2)
Divide equation 1 by 12:
{x+0 y = (-7)/40 | (equation 1)
0 x+y = -11/20 | (equation 2)
Collect results:
Answer: {x = -7/40
, y = -11/20
