X^2+4+10=0
x=(-4(+/-)root16-40)/2, so we now know that the zeros are imaginary, because you can't square root a negative number and 16-40 is -24
so the two roots are…
-2+iroot6 and -2-iroot6
Length = 4w + 2
A = length x width
= (4w + 2) . w
= 4w^2 + 2w ft square
Well, looking at the graph, notice, its vertex is at 0,9, and it passes through the points -3,0 and 3,0, so hmm let's use 3,0, to get the equation of f(x)
It is a it is symmetric on both sides and it’s peak is at 3
