I think 7x-y=-2 is the answer
Answer:
The third one from left to right
Step-by-step explanation:
Just check that when x = 11
y= ![-\sqrt[3]{11-3}+4=-2+4=2](https://tex.z-dn.net/?f=-%5Csqrt%5B3%5D%7B11-3%7D%2B4%3D-2%2B4%3D2)
So the graph passes through the point (11,2)
Data set: <span>2, 10, 10, 11, 11, 12, 12, 12, 13, 14, 14
</span>
range: 14 - 2 = 12
median: 12
lower quartile = 10
interquartile range = 4
Data set w/o outlier 2: <span>10, 10, 11, 11, 12, 12, 12, 13, 14, 14
range: 14 - 10 = 4
median: 12
lower quartile: 10.5
interquartile range = 3.5
The value that change the most by removing the outlier is A.) THE RANGE.</span>
Answer:
Step-by-step explanation:
Challenge # 1
Line has a negative slope with positive slope.
Therefore, equation will be,
y = 1.5x - 6
Parallel line to the given line will have same slope = 1.5 but with different y-intercept.
Equation of the parallel line → y = 1.5x + 6
Challenge # 2
Line has a negative y-intercept = -1 (Approx.)
Slope of the line = negative
Therefore, equation of the line will be,
y = -3.7x -1
Line parallel to the given line will have same slope but different y-intercept.
Equation of the parallel line → y = -3.7x + 1
Challenge # 3
Line with negative slope and no y-intercept.
y = -0.8x
Parallel line to the given line will have same slope and different y-intercept.
Equation of the parallel line → y = -0.8x + 1
Challenge # 4
Line in the graph has positive slope and negative y-intercept.
y = -5 + 4.2x
Line parallel to the given line will have same slope but different y-intercept.
Equation of the parallel line → y = - 7 + 4.2x
