Heat = change in internal energy + Work done The internal energy of a system = heat added and mechanical work done by the system, i.e. U = Q + W rearranging the formula above, will give us: Q = deltaU + W
Q = U - W = 604 kJ - 43.0 kJ = 561,000 J would be the answer.
Answer:
The ratio of the new force over the original force is 16
Explanation:
Recall the formula for the gravitational force between two masses M1 and M2 separated a distance D:
![F_G=G\,\frac{M_1\,\,M_2}{D^2}](https://tex.z-dn.net/?f=F_G%3DG%5C%2C%5Cfrac%7BM_1%5C%2C%5C%2CM_2%7D%7BD%5E2%7D)
So now, if the masses M1 and M2 are quadrupled and the distance stays the same, the new force becomes:
![F'_G=G\,\frac{4M_1\,\,4M_2}{D^2}=G\,\frac{16\,\,M_1\,\,M_2}{D^2}=16\,\,G\,\frac{M_1\,\,M_2}{D^2}= 16\,\,F_G](https://tex.z-dn.net/?f=F%27_G%3DG%5C%2C%5Cfrac%7B4M_1%5C%2C%5C%2C4M_2%7D%7BD%5E2%7D%3DG%5C%2C%5Cfrac%7B16%5C%2C%5C%2CM_1%5C%2C%5C%2CM_2%7D%7BD%5E2%7D%3D16%5C%2C%5C%2CG%5C%2C%5Cfrac%7BM_1%5C%2C%5C%2CM_2%7D%7BD%5E2%7D%3D%2016%5C%2C%5C%2CF_G)
which is 16 times the original force.
So the ratio of the new force over the original force is 16