The force of static friction keeps a stationary object at rest. Once the force of static friction is overcome, the force of kinetic friction is what slows down a moving object.
As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf. ... Like low-mass stars, high-mass stars are born in nebulae and evolve and live in the Main Sequence
hydrogen shell burning - outer layers swell. Red Giant Branch - helium ash core compresses - increased hydrogen shell burning. First Dredge Up - expanding atmosphere cools star - stirs carbon, nitrogen and oxygen upward - star heats up.
Answer:
The minimum thickness = 83.92 nm
Explanation:
The relation between the wavelength in a particular medium and refractive index 
where ;
= wavelength of the light in vacuum
n = refractive index of medium with respect to vacuum
For one phase change :
Replacing 1.43 for n and 480 nm for λ; we have:
t = 83.92 nm
Thus; the minimum thickness = 83.92 nm
Answer:
b. a large elliptical galaxy
Explanation:
In elliptical galaxies the stars are grouped in an elliptical shape, it has a low quantity of gas and dust in comparison to spiral galaxies, and its stars belong to an old population, there is not new stellar formation in it.
The stars orbit in a messy way which made to believe that they form from the merger of galaxies.
They are also really massive (around 
solar masses).
The most massive and luminous can be found in the center of cluster of galaxies.
Answer: 888.45 K or 615.3 °c
Explanation:
According to Gay Lussacs law which states that at constant volume, pressure of an ideal gas is directly proportional to it's absolute temperature.
P/T = Constant
Therefore, P1/T1 = P2/T2
P1 = 6.7 atm
T1= 23°c = 273.15 + 23 = 296.15K
Since P2 is tripled, then,
P2 = 6.7 x 3= 20.1 atm
T2 = (20.1 x 296.15) ÷ 6.7
T2 = 888.45 K
Or in celcius 615.3°c
