On connecting a 9V battery to a Capacitor consisting of two circular plates of radius 0.066 m separated by an air gap of 2. 0 mm. The charge on the positive plate is 544.7 ×10⁻¹² C.
Capacitance of the capacitor is determined by the area of the plate of Capacitor and distance between the plates of capacitor.
Let the area of the Capacitor be A , radius of circular plates be r and distance between the plates of capacitor be d.
Given, Voltage, V = 9V
Radius, r = 0.066m
Distance, d = 2mm = 0.002m
Area of the Capacitor, A = πr²
A = π(0.066)²
A = 0.013m²
Capacitance, C = ε₀A / d
C = 8.85×10⁻¹²×0.013/0.002
C = 60.5 ×10⁻¹² F
C = 60.5 pF
We know that Q = CV where Q is the charge on capacitor.
Q = 60.5 ×10⁻¹² × 9
Q= 544.7 ×10⁻¹² C
Since, both plates of a capacitor acquire equal and opposite charge.
Hence the charge on the positive plate of the capacitor is 544.7 ×10⁻¹² C.
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Explanation:
doesn’t corrode easily and is soft enough for inexpensive tools to cut to the needed individual patterns.
The correct answer for the question that is being presented above is this one: "D. smaller than." In a practical machine, the power output is smaller than the power input. The power output is smaller than the power input as most of the energy usually has been converted to heat in the process.
Answer:
a) 10.29° upstream
b) t=338.7s
Explanation:
If the river is 1km wide and the destination point is 0.5km away downstream, then the angle and distance the the boat has to travel is:
The realitve velocity of the boat respect to the water is:
where β is the angle it has to be pointed at.
From the relative mvement equations:
where
From this equation we get one equation per the x-axis and another for the y-axis. If we square each of them and add them together, we will get 2 equations:
Solving for V:
V = 3.3m/s and V=-1.514m/s Replacing this value into one of our previous x or y-axis equations:
The amount of time:
Answer:
Diffraction equation applies in this case:
d*Sin x = m*wavelength, where d = spacing of lines, x = angle = 39.5°, m = order of maximum = 2
Substituting;
d* Sin 39.5 = 2*600*10^-9
d = (2*600*10^-9)/Sin 39.5 = 1.88656*10^-6 m
In 1 mm (or 0.001 m), the number of lines is given as;
Number of lines = 0.001/d = 0.001/(1.88656*10^-6) = 530.065 ≈ 530 lines