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Nonamiya [84]
2 years ago
11

Which of the following are steps in practical problem solving?

Mathematics
1 answer:
finlep [7]2 years ago
8 0

Answer:

Assign an identifying variable to the quantity to be found. Write a sentence stating conditions placed on the quantity. Solve the sentence for the variable.

Step-by-step explanation:

can you mark me as brainlist

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What is an equation in slope-intercept form of the line that passes through (6, −7)
Ber [7]

Answer:

y = -7/6x

Step-by-step explanation:

y - y1 = m*(x-x1)

m=y/x

y - (-7) = -7/6*(x-6)

y + 7 = -7/6x + 7

y = -7/6x + 7 - 7

y = -7/6

4 0
3 years ago
Schoolyard has an area of 3,564ft.² the section that is in the shape of a triangle is just for picnic table and what is the area
asambeis [7]

Answer:

The area of the section for the picnic tables is 1,188\ ft^{2}

Step-by-step explanation:

we know that

The area of the schoolyard is equal to the area of a rectangle plus the area of a triangle

so

3,564=44*(2x-x)+\frac{1}{2}(2x-x)*44\\ \\3,564=44x+22x\\\\3,564= 66x\\ \\x=54\ ft

The area of the triangle is equal to

22x=22*54=1,188\ ft^{2}

6 0
3 years ago
Find the volume of the wedge-shaped region contained in the cylinder x2 + y2 = 49, bounded above by the plane z = x and below by
fiasKO [112]
\displaystyle\iiint_R\mathrm dV=\int_{y=-7}^{y=7}\int_{x=-\sqrt{49-y^2}}^{x=0}\int_{z=x}^{z=0}\mathrm dz\,\mathrm dx\,\mathrm dy

Converting to cylindrical coordinates, the integral is equivalent to

\displaystyle\iiint_R\mathrm dV=\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}\int_{z=r\cos\theta}^{z=0}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}-r^2\cos\theta\,\mathrm dr\,\mathrm d\theta
=-\displaystyle\left(\int_{\theta=\pi/2}^{3\pi/2}\cos\theta\,\mathrm d\theta\right)\left(\int_{r=0}^{r=7}r^2\,\mathrm dr\right)
=\dfrac{2\times7^3}3=\dfrac{686}3
4 0
3 years ago
In the definition of fractional numbers, b ≠ 0. Why?
Nataliya [291]
I have no idea. Just commenting to get the answer when someone else knows it
6 0
3 years ago
brooke found the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form as follows​
Goryan [66]

Answer:

The equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is \mathbf{y=-4x-3}

Step-by-step explanation:

Equation of line passing through the points (-7,25) and (-4,13) in slope-intercept form.

The general equation of slope-intercept form is: y=mx+b

First we need to find slope

The formula used for finding slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

We are given: x_1=-7, y_1=25, x_2=-4, y_2=13

Putting values in formula and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{13-25}{-4-(-7)}\\Slope=\frac{13-25}{-4+7}\\Slope=\frac{-12}{3}\\Slope=-4

So, slope m= -4

Now finding y-intercept

Using slope m=-4 and point (-7,25) we can find y-intercept

y=mx+b\\25=-4(-7)+b\\25=28+b\\b=25-28\\b=-3

So, y-intercept b =-3

Now, the equation of required line having slope m=-4 and  y-intercept b=-3 is:

y=mx+b\\y=-4x-3

So, the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is \mathbf{y=-4x-3}

3 0
3 years ago
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